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iogann1982 [59]
3 years ago
15

An aquarium 4 ft long, 1 ft wide, and 2 ft deep is full of water. (give your answers correct to the nearest whole number.)

Mathematics
1 answer:
Radda [10]3 years ago
8 0
V = l * w * h
V = 4 ft * 1 ft * 2ft
V = 8ft
If you’re looking for volume.
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Can someone help me understand this.​
3241004551 [841]

Answer:

easy-peasy

Step-by-step explanation:

Perimeter:

P=2(a+b)

P=2(50+70)

P=2(120

P=240

Area:

A=50*70

A=3,500

I really hope it helped:)

8 0
3 years ago
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Х<br> Solve for x.<br> 43°<br> 22
Anastaziya [24]
11.3 did that help you
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3 years ago
3x-2=2(x-5)<br><br>find the value of x ​
kipiarov [429]

Now we have to,

find the required value of x.

Let's begin,

→ 3x-2 = 2(x-5)

→ 3x-2 = 2x-10

→ 3x-2x = -10+2

→ x = -8

Hence, value of x is -8.

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3 years ago
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Currently, the demand equation for necklaces is Q = 30 – 4P. The current price is $10 per necklace. Is this the best price to ch
barxatty [35]

Answer:

The correct answer is NO. The best price to be charged is $3.75

Step-by-step explanation:

Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.

⇒ 4P = 30 - Q

⇒ P = \frac{30-Q}{4}

The current price of the necklace $10.

Revenue function is given by R = P × Q = \frac{1}{4} × ( 30Q - Q^{2})

To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.

\frac{dR}{dQ} =  \frac{1}{4} × ( 30 - 2Q) = 0

⇒ Q = 15.

The second order derivative is negative showing that the value of Q is maximum.

Therefore P at Q = 15 is $3.75.

Thus to maximize revenue the price should be $3.75.

6 0
3 years ago
Alice and Bill are planning to have three children. (Assume that it is equally likely for a boy or a girl to be born.) What is t
zhuklara [117]

Answer:

\frac{1}{8}

Step-by-step explanation:

Alice and Bill  are planning to have three children

We have to find the probability that all three of their children will be girl.

Sample space =S={BBB,BBG,BGB,GBB,GGG,GBG,GGB,BGG}

Total =8

Number of cases in which all three children are girls={GGG}

Probability,P(E)=\frac{number\;of\;favorable\;cases}{Total\;number\;of cases}

Using the formula

Then , the probability that all three of their children will be girls=\frac{1}{8}

6 0
4 years ago
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