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3 years ago

5

Point A (2,5) is dilated from the Irgun with the scale factor 3, resulting in point A'. Darius says the coordinates of point A a

re (6,15). Marcia says the coordinates of point A are (4,13). Who is correct?

2 answers:

Elenna [48]3 years ago

6 0

Answer:marcia

Step-by-step explanation:

Artyom0805 [142]3 years ago

3 0

Answer:

the answer is Darius says the coordinate of point A are (6,15)

Step-by-step explanation:

You might be interested in

The nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium. To determine if the

lora16 [44]

Answer:

We conclude that the sodium content is same as what the nutrition label states.

Step-by-step explanation:

We are given that the nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium.

The FDA randomly selects 40 packages of Oriental Spice Sauce and determines the sodium content. The sample has an average of 1088.64 milligrams of sodium per package with a sample standard deviation of 234.12 milligrams.

<u><em /></u>

<u><em>Let </em></u> $\mu$ <u><em> = average sodium content.</em></u>

So, Null Hypothesis, $H_0$ : $\mu$ = 1100 milligrams {means that the sodium content is same as what the nutrition label states}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 1100 milligrams {means that the sodium content is different from what the nutrition label states}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample average sodium content = 1088.64 milligrams

s = sample standard deviation = 234.12 milligrams

n = sample of packages of Oriental Spice Sauce = 40

So, <u><em>test statistics</em></u> = $\frac{1088.64-1100}{\frac{234.12}{\sqrt{40}}}$ ~ $t_3_9$

= -0.307

The value of z test statistics is -0.307.

<em>Since, in the question we are not given the level of significance so we assume it to be 5%. </em><em>Now, at 0.05 significance level the t table gives critical values of -2.0225 and 2.0225 at 39 degree of freedom for two-tailed test.</em><em> </em>

<em>Since our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the sodium content is same as what the nutrition label states.

3 0

4 years ago

Every 1/2 hour Naomi stretches her neck;every 1/3 hour we stretches her legs and every 1/6 hour she stretches her arms. Which pa

Dmitrij [34]

Answer:

She will have stretched her neck 1 time, she will have stretched her legs 2 times, and she will have stretched her arms 4 times.

Step-by-step explanation:

This is because 1/2 can only go into 2/3 once, 1/3 can go into 2/3 twice, and 1/6 can go into 2/3 four times.

4 0

3 years ago

Which is an asymptote of the graph of the function y = cot ( x - 2pi / 3 )

vesna_86 [32]

$\bf y=cot\left(x-\frac{2\pi }{3} \right)\implies y=\cfrac{cos\left(x-\frac{2\pi }{3} \right)}{sin\left(x-\frac{2\pi }{3} \right)}$

now, if the denominator turns to 0, the fraction becomes undefined, and you get a "vertical asymptote" when that happens, so let's check when is that

$\bf sin\left(x-\frac{2\pi }{3} \right)=0\implies sin^{-1}\left[ sin\left(x-\frac{2\pi }{3} \right) \right]=sin^{-1}(0)
\\\\\\
x-\frac{2\pi }{3}=
\begin{cases}
0\\
\pi 
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{2\pi }{3}\\
\frac{5\pi }{3}
\end{cases}$

now, at those angles, the function is asymptotic, check the picture below

3 0

4 years ago

Read 2 more answers

Pls help with question 5 i’ll be giving a brainliest

Klio2033 [76]

Answer:

Hello there!

The answer you are looking for is B.!

Step-by-step explanation:

That is the only one that makes sense.

Have a great day!

8 0

3 years ago

You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 35 bacteria reveals a sampl

pickupchik [31]

Answer: Sample size would be 296.

Step-by-step explanation:

Since we have given that

Standard deviation = 4.8 hours

Margin of error = 0.65 hours

At 98% level of confidence, z = 2.33

So, It becomes,

$0.65=z\times \dfrac{\sigma}{\sqrt{n}}\\\\0.65=2.33\times \dfrac{4.8}{\sqrt{n}}\\\\\dfrac{2.33\times 4.8}{0.65}=\sqrt{n}\\\\n=(\dfrac{11.184}{0.65})^2\\\\n=17.206^2\\\\n=296.051$

Hence, sample size would be 296.

7 0

3 years ago