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3 years ago

In a discus competition, an athlete threw the discus 63.37 meters, and 63.7 meters.Order the distances from least to greatest

Mathematics

1 answer:

andriy [413]3 years ago

5 0

62.95, 63.37, 63.7 is least to the greatest.

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What is the cost of 1.25kg of cheese at $16 per kilogram?

Svetradugi [14.3K]

Answer:

$20

Step-by-step explanation:

1.25 x $16 = $20

multiply the weight by the price per weight unit (kg).

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3 years ago

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(3x+2)+(2x^2+3x-1)<br><br> Please answer ty:)

Paul [167]

Answer = 2x^2+6x+1

3x+2+2x^2+3x-1
3x+1+2x^2+3x
Now combine like terms
3x+1+2x^2+3x
6x+1+2x^2
Rearrange terms
6x+1+2x^2
2x^2+6x+1

4 0

2 years ago

PLZ HELP !! Which of the points (s, t) is not one of the vertices of the shaded region of the

stira [4]

Answer:

A(0,10)

Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

s ≥ 10 -t (2)

s ≤ 20-t (3)

s ≥ 0

t ≥ 0

Let analyse all 4 possible answer:

A(0, 10)

Let substitute this point into (1) we have: 10 ≥ 12 -0.5*0 Wrong

We do not choose A

B (0, 20)

Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

We choose B as the vertex

C. (4, 16)

Let substitute this point into (1) we have: 16 ≥ 12 -0.5*4 True

Let substitute this point into (2) we have: 16 ≥ 10 - 4 True

Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

We choose C as the vertex

D. (16,4)

Let substitute this point into (1) we have: 4 ≥ 12 -0.5*16 True

Let substitute this point into (2) we have: 4 ≥ 10 - 16 True

Let substitute this point into (3) we have: 4 ≤ 20 - 16 True

We choose B as the vertex

Hence, the point A(0,10) is not one of the vertices of the shaded region of the set of inequalities.

3 0

3 years ago

Let f(x) = x^2 – 81. Find f–1(x). <br> Can someone double-check what I have?

Trava [24]

I hope this helps you

y=x^2-81

x^2=y+81

x=square root of y+81

f^-1 (x)= square root of x+81

5 0

3 years ago

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4 red balls 4 white balls what is the probability of drawing at least 1 red ball if two balls are drawn

vodomira [7]

The probability of drawing exactly one red ball is given by:
$P(1\ red\ ball)=\frac{4C1\times4C1}{8C2}=\frac{16}{28}$
the probability of drawing two red balls is given by:
$P(2\ red\ balls)=\frac{4C2\times4C0}{8C2}=\frac{6}{28}$
The probability of drawing at least one red ball is:
P(1 red ball) + P(2 red balls) = 16/28 + 6/28 = 11/14.
The answer is $\ \frac{11}{14}$

7 0

3 years ago