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NNADVOKAT [17]
3 years ago
14

In a discus competition, an athlete threw the discus 63.37 meters, and 63.7 meters.Order the distances from least to greatest

Mathematics
1 answer:
andriy [413]3 years ago
5 0
62.95, 63.37, 63.7 is least to the greatest.
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Please help!! Thank you so much!!
Olenka [21]

Answer:

AC, AB, BC

Step-by-step explanation:

3x-13+2x-20+x+15=180

6x-18=180

6x=198

x=33

<a 86

<b 46

<c48

3 0
2 years ago
You hang two strands of decorative lights.
Sphinxa [80]

Answer:

The stands will change color at the same time after 54 seconds.

Step-by-step explanation:

Find the Lcm number of both number (18 and 27)

The answer will be 54

5 0
2 years ago
Can someone please help me with this question?!? I am so confused and I don't know how to answer it.
lbvjy [14]

9514 1404 393

Answer:

  a. f(0) = 1

  b. DNE (does not exist)

  c. DNE

  d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

  f(0) = 1

 f(2) does not exist. There is a "hole" in the function definition there.

__

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

__

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

__

In summary, ...

  a) f(0) = 1

  b) lim x → 0 does not exist

  c) f(2) does not exist

  d) lim x → 2 = 3

_____

<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

6 0
2 years ago
PLEASE helppp. What equation describes a line that is perpendicular y=-2/7x+5 and has the same y-intercept as y = 3x - 2?
svp [43]

Answer:

y = 7/2 -2

Step-by-step explanation:

if the slope of the first problem is -2/7 then its perpendicular is 7/2 (the exact opposite) and since the y- intercept is the b in Y= mx +b the intercept of the equation you’re trying to find is -2

6 0
3 years ago
Choose the item that does NOT have a measurable volume.
Tanzania [10]

Answer:

two dimensional triangle

Step-by-step explanation:

im not smart but im pretty sure its that

4 0
2 years ago
Read 2 more answers
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