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katovenus [111]
2 years ago
13

What is the expression in radical form?

Mathematics
1 answer:
Helen [10]2 years ago
8 0

Answer:

the answer is b

Step-by-step explanation:

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Simplify the expression 1.5y2+6.3+6y-3.9-4y+y2​
Lena [83]

Answer: 2.5y^{2} +2y+2.4

Step-by-step explanation:

8 0
3 years ago
Is this statement true or false explain why 6,203 > 6,320
harina [27]

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false

Step-by-step explanation:

3 0
3 years ago
What should be subtracted from 3x^4 - 2x^3 + 2x^2 + 3x - 2x + 3, so that the resulting polynomial is exactly​
lbvjy [14]

Answer:

185/27

Step-by-step explanation:

To get the polynomial that is exactly divisible by g(x)=3x+2, we have to divide f(x)=3x

4

−2x

3

+3x

2

−2x+3 by g(x) and get the remainder as shown in the above image.

Hence,  

27

185

​

 should be subtracted from 3x

4

−2x

3

+3x

2

−2x+3 so that the resulting polynomial is exactly divisible by 3x+2.

8 0
2 years ago
Help me please ASAP please help
Mekhanik [1.2K]

Answer:

the volume is 15.7 in. 3............

4 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
11Alexandr11 [23.1K]
<h3>Answer: B) Only the first equation is an identity</h3>

========================

I'm using x in place of theta. For each equation, I'm only altering the left hand side.

Part 1

cos(270+x) = sin(x)

cos(270)cos(x) - sin(270)sin(x) = sin(x)

0*cos(x) - (-1)*sin(x) = sin(x)

0 + sin(x) = sin(x)

sin(x) = sin(x) ... equation is true

Identity is confirmed

---------------------------------

Part 2

sin(270+x) = -sin(x)

sin(270)cos(x) + cos(270)sin(x) = -sin(x)

-1*cos(x) + 0*sin(x) = -sin(x)

-cos(x) = -sin(x)

We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.

7 0
3 years ago
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