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V125BC [204]
3 years ago
12

What does a professional programmer usually do first to gain an understanding of a problem?

Computers and Technology
2 answers:
ElenaW [278]3 years ago
6 0
The correct answer to your question is:

Professional programmers work directly with, and interview customers to find out what the problem is.
Nadya [2.5K]3 years ago
6 0

Answer and explanation:

Before even starting encoding, a professional programmer should <em>find out what is the customer looking</em> for to have a general idea of what the programming will be like. This does not imply during the process of encoding the professional will not take the customer idea's into consideration to get to the final work result.

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Which hexadecimal number is equivalent to the decimal number 11?
Elina [12.6K]
1011, hope that helps.
8 0
3 years ago
In python please:
Vikki [24]

Answer:

"

if 'marsupial' in dictionary:

   del dictionary['marsupial']

else:

   print("The key marsupial is not in the dictionary")

"

Explanation:

So you can use the keyword "in" to check if a certain key exists.

So the following code:

"

if key in object:

   # some code

"

will only run if the value of "key" is a key in the object dictionary.

So using this, we can check if the string "marsupial' exists in the dictionary.

"

if 'marsupial' in dictionary:

   # code

"

Since you never gave the variable name for the variable that references a dictionary, I'm just going to use the variable name "dictionary"

Anyways, to delete a key, there are two methods.

"

del dictionary[key]

dictionary.pop(key)

"

Both will raise the error "KeyError" if the key doesn't exist in the dictionary, although there is method with pop that causes an error to not be raised, but that isn[t necessary in this case, since you're using the if statement to check if it's in the dictionary first.

So I'll just use del dictionary[key] method here

"

if 'marsupial' in dictionary:

   del dictionary['marsupial']

else:

   print("The key marsupial is not in the dictionary")

"

The last part which I just added in the code is just an else statement which will only run if the key 'marsupial' is not in the dictionary.

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