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3 years ago

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On Saturday, Nikki and Tyler walked to the local farmer’s market. Nikki bought 8 apples for $6. Tyler bought 3 fewer apples than

Nikki. How much did Tyler spend on apples?
$

2 answers:

Ainat [17]3 years ago

8 0

Answer:

The answer is $3.75

Step-by-step explanation:

I just answered the question on ed.

Tems11 [23]3 years ago

4 0

Answer:

$3.75

Step-by-step explanation:

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A ski area has a high-speed lift that can move 2,400 skiers to the top of the mountain each hour. Write an expression describing

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Answer:

2,400h

Step-by-step explanation:

You multiply the amount of skiers per hour (2,400) by the amount of hours (h).

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2 years ago

Please don’t answer just for points! Help is really needed~

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2 years ago

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Piper claims that 3(2a + 2) is equivalent to 5a + 6. She checks her claim by substituting -3 for a. Is Piper's claim correct? Wh

Paha777 [63]

Answer:

Piper's claim is not correct.

Step-by-step explanation:

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2 years ago

Javiver has $15 to spend On action figures.If it’s bigger cost two dollars what is the greatest number of action figures he can

FinnZ [79.3K]

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5 0

3 years ago

In preparation for an earnings report, a large retailer wants to estimate p= the proportion of annual sales

mr Goodwill [35]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The sample size and the estimate are given by:

$n = 161, \pi = \frac{37}{161} = 0.2298$

Hence:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 - 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.1648$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 + 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.2948$

The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago