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So we already drew two cards and both of them are spades. So that means there are 50 cards and 11 spades left.
Then third card being spades would be 11 / 50
Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49
Fifth card would be 9 / 48.
So the probability of next three cards being spades would be
Hope this helps.
Then third card being spades would be 11 / 50
Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49
Fifth card would be 9 / 48.
So the probability of next three cards being spades would be
Hope this helps.
<u>Given</u>:
Given that in a game a player draws and replaces a card from a deck 2 times.
The possible outcomes and payouts are given.
We need to determine the expected value for someone playing the game.
<u>Expected value:</u>
The expected value for someone playing the game can be determined by
Simplifying the values, we have;
Dividing the terms, we get;
Adding, we have;
Thus, the expected value for someone playing the game is $8