That would be A :D It would be A because you would do keep change flip. You would keep 5/6, change the division sign to multiplication, then flip the 5/16 to 16/5 (the reciprocal)
So we already drew two cards and both of them are spades. So that means there are 50 cards and 11 spades left.
Then third card being spades would be 11 / 50
Now there are 10 spades and 49 cards left.
So the probability for fourth card would be 10 / 49
Fifth card would be 9 / 48.
So the probability of next three cards being spades would be

Hope this helps.
All real numbers is the answer
<u>Given</u>:
Given that in a game a player draws and replaces a card from a deck 2 times.
The possible outcomes and payouts are given.
We need to determine the expected value for someone playing the game.
<u>Expected value:</u>
The expected value for someone playing the game can be determined by

Simplifying the values, we have;

Dividing the terms, we get;

Adding, we have;

Thus, the expected value for someone playing the game is $8