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2 years ago

In a week, 15 hens laid 75 eggs, what is the unit rate for eggs per hen?

Mathematics

2 answers:

masya89 [10]2 years ago

7 0

75 divided by 15 is 5. 5 eggs per hen.

Leya [2.2K]2 years ago

4 0

Laid eggs by 15 hens = 75
laid eggs by a hen
(75/15) * 1
5 eggs/hen

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The mean absolute deviation is a measure of . This value represents the average distance each value is from the .

Oksanka [162]

Answer:

Step-by-step explanation:

Yes

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3 years ago

A car's rear windshield wiper rotates 130°. The total length of the wiper mechanism is 25 inches and the length of the wiper bla

Delicious77 [7]

The area wiped by the viper blade is approximately 486.7 square inches.

The area wiped by the wiper blade ( $A$ ), in square inches, is equal to the area of the circular section described below:

$A = \frac{\theta\cdot \pi}{360}\cdot (R^{2}-r^{2})$ (1)

Where:

$\theta$ - Angle, in sexagesimal degrees.
$r$ - Inner radius, in inches.
$R$ - Outer radius, in inches.

If we know that $\theta = 130^{\circ}$ , $R = 25\,in$ and $r = 14\,in$ , then the area wiped by the wiper blade is:

$A = \frac{130\pi}{360} \cdot [(25\,in)^{2}-(14\,in)^{2}]$

$A \approx 486.7\,in^{2}$

The area wiped by the viper blade is approximately 486.7 square inches.

We kindly invite to check this question on circular sections: brainly.com/question/14989543

8 0

2 years ago

Pls answer no is answering mine

weeeeeb [17]

Answer:

Step-by-step explanation:

By doing the unit rate, dividing 19 on both the top and bottom, getting this 8.36.../1, you can just round it to 8/1, meaning he makes about 8 deliveries per hour. Hope this helps!

3 0

2 years ago

The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra

kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

opera house ticket = $52

attendance = 3800 person

assuming these are the points on the demand curve

(x, p) = (4000,50) and (x,p) = (3800,52)

using point slope formula

$p-50 = \dfrac{50-52}{4000-3800}(x - 4000)$

$p-50 = \dfrac{-2}{200}(x - 4000)$

$p-50 = \dfrac{-x}{100}+ 40$

$p = \dfrac{-x}{100}+ 90$

R(x) = x . p

$R(x) = x (\dfrac{-x}{100}+ 90)$

$R(x) = \dfrac{-x^2}{100}+ 90x)$

$\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))$

$\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)$

at $\dfrac{d}{dx}(R(x)) = 0$

$\dfrac{-2x}{100}= -90$

x = 4500

$\dfrac{d^2}{d^2x}(R(x)) = -ve$

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

$p = \dfrac{-4500}{100}+ 90$

p = $45

6 0

2 years ago

Number 18.

Rashid [163]

f(x) = -5/2x + 4

f(3) = (-5/2)(3) + 4

f(3) = -15/2 + 4

f(3) = -7.5 + 4

f(3) = -3.5

Answer: B. –3.5

4 0

2 years ago