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aleksklad [387]
3 years ago
5

Find the value of x to the nearest tenth. 10.0 6.0 9.3 4.0

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
7 0
Suppose that the value of other ratio is equal to 6/3 then,

20/3x-8 = 6/3
18x-48 = 60
18x = 60+48
18x = 108
x = 6
sesenic [268]3 years ago
5 0

Answer:

The value of x is 6  

Step-by-step explanation:

Given the figure in which

DE=3x-8 and BC=20

we have to find the value of x.

By mid-point theorem which states that the line segment which is drawn to the mid-points of two sides of triangle is parallel to the third side and also half of the length of third side.

DE=\frac{1}{2}BC

(3x-8)=\frac{1}{2}\times 20

3x-8=10

3x=18

x=\frac{18}{3}=6

The value of x is 6

Option 2 is correct.

You might be interested in
PLZZZ HELP WILL MAKE BRAINLY
attashe74 [19]

Answer:

56

Step-by-step explanation:

To divide 364 into two parts in the ratio 15:11, add 15+11 to get 26. Now divide 364 by 26 to get 14. This counters 14 for each part, and we have 26 parts. If each part is x, and x=14, x times 15 will equal 15x=210, so the first number is 210. x times 11 will equal 11x=154, so the second number is 154. 210-154=56, so the first number is 56 bigger than the second.

4 0
2 years ago
You have a total of ​$1760 to invest. Account A pays 7​% annual interest and account B pays 4​% annual interest. How much should
posledela

Answer:

You should invest $820 in account A and $940 in account B

Step-by-step explanation:

* Lets use the system of linear equations to solve the problem

- Simple Interest Equation I = Prt , Where:

# P = Invested Amount

# I = Interest Amount

# r = Rate of Interest per year in decimal; r = R/100

# t = Time Period involved in months or years

* Lets solve the problem

- The total money invested is $1760

- Account A pays 7​% annual interest

- Account B pays 4​% annual interest

- Let A represent the amount of money invested in the account A

- Let B represent the amount of money invested in the account B

- You would like to earn $ 95 at the end of one year

∴ The interest from both accounts at the end of one year is $95

- Lets write the equations

# Account A :

∵ Account A has $A invested

∴ P = $A

∵ Account A pays 7​% annual interest

∴ r = 7/100 = 0.07

∵ t = 1 year

∵ I = Prt

∴ I = A(0.07)(1) = 0.07A

# Account B :

∵ Account B has $B invested

∴ P = $B

∵ Account A pays 4​% annual interest

∴ r = 4/100 = 0.04

∵ t = 1 year

∵ I = Prt

∴ I = B(0.04)(1) = 0.04B

- The total amount of interest from both accounts at the end of one

  year is $95

∴ I from A + I from B = 95

∴ 0.07A + 0.04B = 95 ⇒ multiply both sides by 100

∴ 7A + 4B = 9500 ⇒ (1)

- The total money to invest in both accounts is $1760

∵ Account A has $A invested

∵ Account B has $B invested

∴ A + B = 1760 ⇒ (2)

* Lets solve the system of equations to find the amount of money

  invested in each account

- Multiply equation (2) by -4 to eliminate B

∵ A + B = 1760 ⇒ × -4

∴ -4A - 4B = -7040 ⇒ (3)

- Add equation (1) and (3)

∵ 7A + 4B = 9500 ⇒ (1)

∵ -4A - 4B = -7040 ⇒ (3)

∴ 7A - 4A = 9500 - 7040

∴ 3A = 2460 ⇒ divide both side by 3

∴ A = 820

- Substitute the value of A in equation (1) or (2)

∵ A + B = 1760 ⇒ (2)

∴ 820 + B = 1760 ⇒ subtract 820 from both sides

∴ B = 940

- From all above

* You should invest $820 in account A and $940 in account B

6 0
3 years ago
3) The equation 41.44=k7 shows that buying 7 bags of apples
Radda [10]

Answer:

1 bag of apples would cost $5.92.

Step-by-step explanation:

All you have to do is take the 41.44 and divide it by 7 to see how much one bag would cost. I used a calculator and got $5.92.

Hope this helps!

7 0
3 years ago
3ln(4x)=13
Kryger [21]
3 * ln 4x = 13 

<span><=> </span>

<span>ln 4x = 13/3 </span>

<span><=> </span>

<span>4x = e^(13/3) </span>

<span><=> </span>

<span>x = e^(13/3) / 4 </span>

<span><=> </span>

<span>x ~ 19.05 </span>
5 0
3 years ago
What is 50,000,000,000 200,000 30,000 in standard form
Stolb23 [73]
50000230000 is how to write 50,000,000,000 + 200,000 + 30,000 in standard form.
6 0
3 years ago
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