Answer:
(4,0)
Step-by-step explanation:
we have
----> inequality A
----> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
Verify each ordered pair
case 1) (4,0)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>
----> is true
so
the ordered pair makes both inequalities true
case 2) (1,2)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 3) (0,4)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 4) (2,1)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>
----> is not true
so
the ordered pair not makes both inequalities true
1. To solve this problem, it is important to know that<span> the logarithmic functions and the exponential functions are inverse. Then, you have:
</span><span>
e^a=28.37
</span><span> a=ln(28.37)
</span><span>
2. Therefore: </span><span>Which logarithmic equation is equivalent to the exponential equation e^a=28.37? A</span><span>s you can see, the answer for this question is:
</span><span>
a=ln(28.37)</span>
Answer:
hmmmm let me think (wastes time) mhmmmmmmm i seeeeee let me think some more (wastes even more time) ok I think I got it ohhhhh wait nevermind I see (still wastes time) oop nevermind I have no idea
Oh Btw its C
Step-by-step explanation:
Answer:
angle 1 → 45°
angle 2 → 90°
Step-by-step explanation:
Since AC bisects ∠DAB then the measure of angle 1 is 90/2 = 45°
Since Lines AC and BD are perpendicular then the measure of angle 2 is 90°
So a circle is divided into 360 equal degree,so that a right angle ie 90 degree
