What is the degree of v7

Solve the system of linear equations below.

UkoKoshka [18]

Answer:

A

Step-by-step explanation:

6x+3y=33 <=> 2x+y=11<=>4x+2y=22 (1)

4x+y=15 (2)

(1)-(2) <=> y=7

3 0

3 years ago

Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights

user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that $\mu = 85, \sigma = 8$

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{100 - 85}{8}$

$Z = 1.875$

$Z = 1.875$ has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

$Z = \frac{X - \mu}{\sigma}$

$-0.84 = \frac{X- 85}{8}$

$X - 85 = -0.84*8$

$X = 78.28$

The weight that 80% of the apples exceed is of 78.28g.

5 0

3 years ago

How do you write 900 in expanded form

Dvinal [7]

Well its
900+0+0
basically
like if it was
9,234
then it would be
9000+200+30+4

7 0

4 years ago

Read 2 more answers

What is the mass of 2.5 moles of carbon dioxide?

GarryVolchara [31]

Answer:

110 grams

Step-by-step explanation:

CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).

So first finding the mass of 1 molecule of CO2 which is equals to

= mass of 1 carbon atom + masses of 2 oxygen atom, we get

= 12+(16*2)= 12+32= 44 a.m.u.

Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )

1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams

So our answer is 110 grams.

lowkey hope this helped you, good luck whatever you need it for Imaooo

3 0

3 years ago

If the endpoints of the diameter of a circle are (9, 4) and (5, 2), what is the standard form equation of the circle?

sattari [20]

The standard forrm equation of the circle is (x-h)² + (y-k)² = r²
where h,k : x,y-coordinate of the center
r : radius of the circle
Get the center of the circle : h = (x1 + x2)/2 = (9+5)/2 = 7
k = (y1 + y2)/2 = (4+2)/2 = 3
=> the center is (7,3)
Because the given information gave 2 endpoints so we can choose one of these, then use the distance formula to get the radius
r = √(x1 - h)² + (y1 - k)²
r = √(9 - 7)² + (4 - 3)²
r = √2² + 1²
r = √5
Finally, the equation of the circle is (x - 7)² + (y - 3)² = (√5)²
(x - 7)² + (y - 3)² = 5

4 0

4 years ago