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3 years ago

(2+5i)(6-i) simply ........

Mathematics

2 answers:

satela [25.4K]3 years ago

5 0

Answer:

=17+28i

Step-by-step explanation:

Verizon [17]3 years ago

3 0

Answer:

17+28i

Step-by-step explanation:

TELL ME IF IM RIGHT PLEASR

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PLEASE HELP! 50 POINTS ON THE LINE!

MAVERICK [17]

Answer: hello! I'm here to help.

Let's work the problem using just the thousands and leave the zeros off. We'll add them back at the end.

Let M be the salary of the Master's degree, and B be the salary of the Bachelor's degree.

M + B = 120

M + 39 = 2B

M = 2B - 39

2B - 39 + B = 120

3B - 39 = 120

3B = 159

B = 53

M = 120 - B = 120 - 53 = 67

<h2>PLEASE BRAINLIEST! :)</h2>

8 0

3 years ago

The sum of two numbers is 12 and their difference is 6. What are the two numbers?

wolverine [178]

Answer:

The two numbers are 9 and 3.

Step-by-step explanation:

x+y=12

x-y=6

---------

2x=18

x=18/2

x=9

9-y=6

y=9-6

y=3

4 0

3 years ago

Round 26.86 to the nearest tenth

stealth61 [152]

Answer:

26.9

Step-by-step explanation:

Right now we have '8' in the tenths place. That '6' following the '8' requires us to round up. Thus, 26.86 to the nearest tenth is 26.9.

5 0

3 years ago

Find the counterclockwise circulation and outward flux of the field Fequals7 xy Bold i plus 2 y squared Bold j around and over t

77julia77 [94]

Answer:

The counterclockwise circulation is $\frac{7}{12}$ and the outward flux is $\frac{11}{15}$

Step-by-step explanation:

We are given the field $F(x,y) = (7xy,2y^2)$ . A picture of the region and the path we are considering is attached. Recalll the following theorems.

Given a field of the form F(x,y)=(f(x,y),g(x,y) with f,g having continous partial derivates, C is a closed path counterclockwise oriented, R is the region enclosed by C and n is the normal vector pointing outwards of the path C. Then

$\oint_C F\cdot dr =\iint_R \frac{\partial f}{dy}- \frac{\partial g}{dx} dA$ (this one calculates the counterclockwise circulation)

$\oint_C F\cdot n ds =\iint_R (\frac{\partial f}{dx}+ \frac{\partial g}{dy} dA$ (This one calculates the outward flux)

Then, recall that in our case f(x,y) = 7xy, g(x,y)=2y^2[/tex]. Then

$\frac{\partial f}{dx} = 7y,\frac{\partial f}{dy} = 7x$

$\frac{\partial g}{dx}=0, \frac{\partial g}{dy} = 4y$ .

Note that we just need to describe our region R. The region R lies between the parabola y=x^2 and the line y=x. Thus, one way to describe the region is as follows $0\leq x \leq 1, x^2\leq y \leq x$ . Then, using the previous results, we get that

$\oint_C F\cdot dr =\int_{0}^{1}\int_{x^2}^{x}7x-0dydx = 7\int_{0}^1x(x-x^2)dx = 7 \left.(\frac{x^3}{3}-\frac{x^4}{4})\right|_{0}^1 = 7(\frac{1}{3}-\frac{1}{4}) = \frac{7}{12}$ (circulation)

$\oint_C F\cdot n ds=\int_{0}^{1}\int_{x^2}^{x}7y+4ydydx = \frac{11}{2}\int_{0}^1\left.y^2\right_{x^2}^{x}dx = \frac{11}{2}\int_{0}^{1}x^2-x^4 dx = \frac{11}{2}\left(\frac{x^3}{3}-\frac{x^5}{5})\right|_{0}^{1}=\frac{11}{2}(\frac{1}{3}-\frac{1}{5})=\frac{11}{15}$ (flux)

5 0

3 years ago

Help ASAP please you will get brainly and 28 points

DiKsa [7]

G
If it’s wrong I’m sorry but I’m pretty sure it’s G

5 0

3 years ago