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Readme [11.4K]
3 years ago
9

Which is greater 45 hundredths or 6 tenths

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
45 hundredths is greayer than 6 tenth because 45 is in the hundredths spot and 6 is in the tenth spot
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I WILL MA FIRST ANSWER BRANILIST The map shows the location of the houses of Dan, Joe, Lee, and the coordinates of the community
emmasim [6.3K]
Look at the coordinates. They are both negative. (-5,-1)

Let me plot all the coordinates so you can see:

Joe= (-3,4)

Dan= (1,4)

Roy= (2,-3)

Lee= (-3,-4)

The only person with coordinates that are both negative is Lee.

"C" is the answer. Lee. 

I hope this helps!
~kaikers
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3 years ago
Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
Many bank accounts never go below zero. But some banks will allow a negative balance, at least for a short time, called an overd
cestrela7 [59]

Answer:

46.71 is the answer i hope it will help u .

Step-by-step explanation:

u just subtract the deposited money with he had in 4 week : ) i guss

8 0
3 years ago
members of a cookie club are selling cookie's for $2.50 per box. their goal is to sell enough boxes to total at least $350 in sa
bearhunter [10]

Answer:

They would need to sell more than or equal to 140 boxes of cookies.

Step-by-step explanation:

The equation would be

2.50t >= 350

--------   -------

2.50     2.50

t >= 140

5 0
2 years ago
9 students volunteer for a committee. How many different 7-person committees can be chosen?
lorasvet [3.4K]
If order doesn't matter (e.g. all the positions in the committee are essentially identical) then the number of possible choices is \dbinom97=\dfrac{9!}{7!(9-7)!}=36.
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