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Sedaia [141]
2 years ago
7

Given that m2Q=63 and DQ-7, find z rounded to the nearest tenth.

Mathematics
1 answer:
nasty-shy [4]2 years ago
5 0

Answer:

Ali is a boy

Step-by-step explanation:

Ali is a good boy

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Solve the equation. type the numeral answer. do not round up-5= b - 2.3
ycow [4]

Answer and explanation:

  - 5 = b - 2.3    add 2.3 to both sides

+2.3        +2.3

- 2.7 = b

5 0
4 years ago
Compare the values.<br> 9 x 10^2 is<br> ?<br> times as much as 3 x 10^-2.
barxatty [35]

Answer:

Hopefully this explains o_O, also Merry Christmas!

Step-by-step explanation:

9 x 10^2 = 9 x 100 = 900

3 x 10^-2 = 3 x 1/100 = 0.03

Ratio of 900:0.03

The first one is 30000 bigger than the second

5 0
3 years ago
Read 2 more answers
Would the following situation be better represented by a linear function or an exponential function:
anastassius [24]

Answer:

Exponential function

Step-by-step explanation:

It is better if the situation on ground is represented by an exponential equation.

This is because, since we have the number of teams reducing by exactly half at every playoff round, this means that we have a base of 2 which can be raised to a negative power since we are talking about a decrease.

We can then place the number of rounds as an adjoining power to what the two is raised and this easily will get us the number of teams which is eventually decreased at every point of the playoffs

4 0
3 years ago
One year Roger had the lowest ERA​ (earned-run average, mean number of runs yielded per nine innings​ pitched) of any male p
baherus [9]

Answer:

(a) The <em>z</em>-score of Roger is -1.56 and the <em>z</em>-score of Amber is -1.13.

(b) Roger had a better year relative to his peers.

Step-by-step explanation:

If X follows N (<em>µ, σ</em>₂), then z=\frac{x-\mu}{\sigma}, is a standard normal variate with mean,      E (Z) = 0 and Var (Z) = 1. That is, Z follows N (0, 1).

Let <em>X</em> = ERA of male pitchers and <em>Y</em> = ERA of ERA of female pitchers.

It is provided that the mean and standard deviation of <em>X</em> are:

\mu_{X}=4.371\\\sigma_{X}=0.787

Also, the mean and standard deviation of <em>Y</em> are:

\mu_{Y}=4.363\\\sigma_{Y}=0.869

ER of Roger is 3.14 and ERA of Amber is 3.38.

(1)

Compute the <em>z</em>-score of Roger as follows:

z=\frac{x-\mu_{X}}{\sigma_{X}}=\frac{3.14-4.371}{0.787}=-1.56

Thus, the <em>z</em>-score of Roger is -1.56.

Compute the <em>z</em>-score of Amber as follows:

z=\frac{x-\mu_{Y}}{\sigma_{Y}}=\frac{3.38-4.363}{0.869}=-1.13

Thus, the <em>z</em>-score of Amber is -1.13.

(2)

Compute the probability of ERA's that are greater than Roger's ERA as follows:

P(X>3.14)=P(\frac{X-\mu}{\sigma}>\frac{3.14-4.371}{0.787})\\=P(Z>-1.56)\\=P(Z

This implies that 94% of the other male pitchers had an ERA higher than 3.14.

Compute the probability of ERA's that are greater than Amber's ERA as follows:

P(Y>3.38)=P(\frac{Y-\mu_{Y}}{\sigma_{Y}}>\frac{3.38-4.363}{0.869})\\=P(Z>-1.13)\\=P(Z

This implies that 87% of the other female pitchers had an ERA higher than 3.38.

As it is provided that the lower the ERA the better the pitcher, then it can be concluded that Roger had a better year relative to his peers.

4 0
4 years ago
HELLPPPPP MEEEEE IS DUE TODAY
siniylev [52]

Answer:

= 21.6216% decrease

Step-by-step explanation:

Calculate percentage change

from V1 = 29.6 to V2 = 23.2

(V2−V1)|V1|×100

=(23.2−29.6)|29.6|×100

=−6.429.6×100

=−0.216216×100

=−21.6216%change

=21.6216%decrease

3 0
3 years ago
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