Step-by-step explanation:
Actual graph for this problem is attached below
m∠TUV = 167°
m∠TUL = (x + 11)°
m∠LUV = (11x)°
m∠TUV=
m∠TUL+
m∠LUV
now plug in the angles for each
m∠TUV=
m∠TUL+
m∠LUV
solve the equation for x
Subtract 11 from both sides
divide both sides by 12
x=13
m∠TUL = (x + 11)°
m∠TUL = (13+ 11)°
= (24)°
answer:
24°
Answer:
267 slices of pizza
Step-by-step explanation:
16 x 6 = 276
276 - 9 = 267
Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
Answer:
89 is the maximum number of guests that can be invited within budget .
Step-by-step explanation:
The cleaning charges = $55
Total budget available = $3350
Cost per guest = $37
Now, actual budget available for guest = Total budget - Cleaning Fee
= $3350 - $ 55 = $3,295
Now, cost per head =$ 37
So, number of guests (n) possible in the budget
⇒ n = (Total guest Budget)/ Cost per head
= $3,295 / $37 = $89.05
or, n = $89.05
So, 89 is the maximum number of guests that can be invited within budget .
Answer:
mean for a = 60/10 = 6
mad of a = 2
mean for b = 80/10 = 8
mad of b = 2
Step-by-step explanation:
Mean absolute deviation (MAD) of a data set is the average distance between each data value and the mean. Take each number in the data set, subtract the mean, and take the absolute value. Then take the sum of the absolute values. Now compute the mean absolute deviation by dividing the sum above by the total number of values in the data set. The mean absolute deviation, MAD, is 2.
\frac {1}{n} \sum \limits_{i=1}^n |x_i-m(X)|
m(X) = average value of the data set
n = number of data values
x_i = data values in the set
mean = average.
