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Tanya [424]
2 years ago
8

Which one have is the coldest temperature negative numbers or positive numbers

Mathematics
1 answer:
aalyn [17]2 years ago
6 0

Answer:

Step-by-step explanat số âm vì số âm < số dương mà nhiệt đọ càng thấp thì càng lạnhion:

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PLEASE PLEASE HELPPPPPPP WILL GIVE BRAINLY + POINTS
Natasha_Volkova [10]

Answer:

Amount of chromosones human have is 46

Step-by-step explanation:

23 from ur father 23 from your mother

I'm not sure i understand your questions though

3 0
2 years ago
5x - 7(2- 4x) = <br> 8 - 3(6 - 6x) =<br> 9a - 4(2a + 5) =
kati45 [8]

Answer:

the answer to 5x-7(2-4x)= =33x−14

the answer to 8 - 3(6 - 6x) ==18x−10

the answer to 9a - 4(2a + 5) ==a−20

Step-by-step explanation:


8 0
3 years ago
2. Given square CANE with diagonals
svlad2 [7]
What’s something goes up but never comes down?
6 0
3 years ago
The answer is 915 / 7
Naily [24]

Answer:

If you want 915/7 simplified, it is 130.714285714.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
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