Question

Analyzing the Discrim

Answer 1

The values of x that will give the quadratic equation no real number solutions are -5 and 9

What are real roots of a quadratic equation?

Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.

Analysis:

We have -$x^{2}$ +3x +c = 0

$b^{2}$ - 4ac  is called the discriminant of a quadratic equation.

if $b^{2}$ - 4ac  < 0, then the quadratic equation has no real root.

where a = -1, b = 3 c = c

$(3)^{2}$ -4(-1)c < 0

9 + 4c < 0

4c < -9

c < -9/2

Which means values lower than -9/2 would give the solution no real root.

From, the options,  only -5 would give no real solution, since it is lower than -9/2.

Learn more about real roots of a quadratic equation: brainly.com/question/7784687

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