Ask question

Ask question

All categories

3 years ago

15

Amy raises $58.75 to participate in a walk a thon. Jeremy raises $23.250more than Amy. Oscar raises 3 times as much as Jeremy. H

ow much money does Oscar raise.

2 answers:

Vlad1618 [11]3 years ago

5 0

Amy = 58.75

Jeremy = 58.75 + 23.25 = 82

Oscar = 3*82= 246
Oscar raised 246 dollars

stiv31 [10]3 years ago

3 0

1. 58.75 + 23.25 = 82
2. 82*3 = 246

Oscar raised $246

You might be interested in

(a) Reflect the point (-8, -6)<br> across the x-axis

jekas [21]

Answer:

(-8, 6)

Step-by-step explanation:

Reflecting across x axis = (x, -y)

-(-6) = 6

4 0

2 years ago

The first term of a geometric sequence is 10,000 and the common ratio is 0.4. What

Misha Larkins [42]

$a = 10000$

$r = 0.4 = 4/10 = 2/5$

$a_9 = ar^8 = 10000 × 2^8/5^8$

$a_9 = 10000 × 256/(25 × 25 × 25 × 25)$

$a_9 = 6.5536$

7 0

2 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

3 years ago

Find the area of an equilateral triangle (regular 3 Gon) with the given measurement 9 in perimeter a=SQ.in

blsea [12.9K]

Answer:

3.897 $in^{2}$

Step-by-step explanation:

equilateral triangles are also equiangular, meaning the have equal angles.

Triangle sum theory says that angles of a triangle add up to 180.

That means each angle is 60.

A = bh/2

You need the (h). The base of is 3. Perimeter = 9, so each side is 3

Draw a perpendicular line for the height. The line cuts the base in half (1.5)

Using trigonometry you can find the height.

tan 60° = h/1.5

h = height, 1.5 is half of 3, 60° is the base angle.

multiply each side by 1.5

1.5(tan 60°) = h

h=2.598

then substitute h into formula

A= <u>(2.598)(3) </u>

2

A = 3.897 rounded

4 0

3 years ago

Suppose you want to go to the ice skating rink and it costs $8 to rent ice skates and $3.75 per hour to skate, write an equation

8_murik_8 [283]

Answer:

c=8+3.75x, where:

c is the cost to go to the ice skating ring

x is the number of hours

Step-by-step explanation:

From the information given, the cost to go to the ice skating ring is equal to the cost to rent ice skates plus the result of multiplying the cost to skate per hour for the number of hours and the equation would be:

c=8+3.75x, where:

c is the cost to go to the ice skating ring

x is the number of hours

8 0

2 years ago