The solution to the given system of linear equations is x = 1, y = 2. That is (1, 2)
<h3>Simultaneous linear equations </h3>
From the question, we are to solve the given system of equations
The given system of equations is
4x + y = 6 -----------(1)
2x - 3y = -4 -----------(2)
From the equation (1)
4x + y = 6
y = 6 - 4x ----------(3)
Substitute the value of y into equation (2)
2x - 3y = -4
2x -3(6 - 4x) = -4
2x -18 +12x = -4
2x + 12x = -4 + 18
14x = 14
x = 14/14
x = 1
Substitute the value of x into equation (3)
y = 6 - 4x
y = 6 - 4(1)
y = 6 - 4
y = 2
Hence, the solution to the given system of linear equations is x = 1, y = 2. That is (1, 2)
Learn more on Simultaneous linear equations here: brainly.com/question/13729904
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Step-by-step explanation:
First, they want you to draw an arc centered at the vertex A. It will intersect the lines at two points. One point is B and the other is C.
Next, they want you to draw two more arcs, one at B and one at C. The two arcs must have the same radius. They intersect at point X.
Draw a line from A to X. That's the angle bisector.
Answer:
12k=84
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
If you mean as an equation, it would be 12k=84
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This is the concept of algebra, given that the elevator is 500ft above the ground and it is descending at a steady rate of 5ft/sec. Then height h, at time t of the elevator movement can be modeled by the equation:
h(t)=-5t+500.
The correct answer is h(t)=-5t+500
Answer:
The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the z-score that has a p-value of
.
They randomly survey 387 drivers and find that 298 claim to always buckle up.
This means that ![n = 387, \pi = \frac{298}{387} = 0.77](https://tex.z-dn.net/?f=n%20%3D%20387%2C%20%5Cpi%20%3D%20%5Cfrac%7B298%7D%7B387%7D%20%3D%200.77)
84% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.74](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.77%20-%201.405%5Csqrt%7B%5Cfrac%7B0.77%2A0.23%7D%7B387%7D%7D%20%3D%200.74)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 1.405\sqrt{\frac{0.77*0.23}{387}} = 0.8](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.77%20%2B%201.405%5Csqrt%7B%5Cfrac%7B0.77%2A0.23%7D%7B387%7D%7D%20%3D%200.8)
The 84% confidence interval for the population proportion that claim to always buckle up is (0.74, 0.80).