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3 years ago

Which inequality's solution is graphed here?

Mathematics

2 answers:

nikklg [1K]3 years ago

8 0

The correct answer is D.
2x >= 7-5

2x >= 2

x >= 1

sergeinik [125]3 years ago

4 0

The answer is d hope this helped yhu

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-15 π + 12 π - 5 π =

Annette [7]

Answer:

-8π or −25.13274122

Step-by-step explanation:

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3 years ago

a craft store retailer is using a discount rate of %40 on Christmas scrapbook items if a package of scrapbook paper cost 15.59 w

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38.98 because you get 15.59 and divide that by 40% you get 38.975 but since you're speaking in money it rounds to 38.98

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4 years ago

Please help with my math question on my account :3

Vikki [24]

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okie dokie

Step-by-step explanation:

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3 years ago

Xy′ = √(1 − y2 ), y(1) = 0

tigry1 [53]

Answer:

y=sin(ln(x))

Step-by-step explanation:

First, we have to order the terms as follows and express y' as dy / dx:

$x*\frac{dy}{dx} =\sqrt{(1-y^{2} )} \\\frac{x}{dx}=\frac{dy}\sqrt{(1-y^{2} )}}\\\frac{dx}{x}=\frac{dy}{\sqrt{(1-y^{2} )} }$

Then, we have to integrate

$\int{\frac{dx}{x}=\int{\frac{dy}{\sqrt{(1-y^{2} )} }$

with this solution after integration:

$ln(x)+C1=arcsin(y)+C2$

Then, we have to reorder

$arcsin(y)=ln(x)+C$

and applied Sin function on both sides

$sin(arcsin(y))=sin(ln(x)+C)\\y=sin(ln(x)+C)$

To define the value of C, we use the known point y(1)=0 and replace in the equation

$y=sin(ln(x)+C)\\0=sin(ln(1)+C)\\0=sin(0+C)\\0=sin(C)\\C=arcsin(0)\\C=0$

The function that proves that differential equation is

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3 years ago

Cara grew 4 inches in a second grade and 3in in a third grade. If cara was 44 inches tall at the start of second grade, how tall

ivann1987 [24]

Answer:

51 inches (or 4 feet 2 inches)

Step-by-step explanation:

if she was 44 inches at the start of second grade, grew 4 inches through second, then grew 3 more inches through third grade, she would be 51 inches (Or 4 feet 2 inches)

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3 years ago