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dimaraw [331]
3 years ago
15

Solve system by graphing 2x-6y=12 x+y=2

Mathematics
1 answer:
astraxan [27]3 years ago
5 0
First get y by its self , then graph , find intersection point and plug in x and y to both equations, see if it makes sense , then the solution must be you intersection point

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Can someone pls help me with this?! I’m stumped lol
forsale [732]

Answer:

  • $3.50
  • 24

Step-by-step explanation:

The graph shows you the value stored on the card dropped by $14 when Gina rented 4 videos. Thus the cost of each one is ...

... $14/4 = $3.50

Gina now has $84 on the card, so can rent an additional ...

... $84/$3.50 = 24 . . . . videos

_____

Division is a way to do "repeated subtraction." That is, if we were to subtract $3.50 from $84 repeatedly, we would find we could do it 24 times.

6 0
4 years ago
Identify properties used in each step in rewriting the polynomial expression below: (x + 5) + 3(a + (6x)y) Step 1: (5 + x)+3(a +
8090 [49]
In step 1, the commutative property of addition is used since x + 5 is just equal to 5 + x
In step 2, the associative property of addition is used since x is grouped to the last term.
In step 3, the distributive property of multiplication is used since 3 is multiplied to the terms inside the parenthesis. 
In step 4, multiplication is done.
5 0
3 years ago
What is the geometric mean of 2 and 8?
asambeis [7]

Answer:

The geometric mean of 2 and 8 comes out to equal 4.

Step-by-step explanation:


4 0
3 years ago
How many passwords of 4 digits are there(a)if none of the digits can be repeated?(b)start with 5 and end in an even digit?
liraira [26]

Answer:

5040,56

Step-by-step explanation:

We have to construct pass words of 4 digits

a) None of the digits can be repeated

We have total digits as 0 to 9.

4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)

No of passwords = 10P4

= 10(9)(8)(7)\\=5040

b) start with 5 and end in even digit

Here we restrain the choices by putting conditions

I digit is compulsorily 5 and hence only one way

Last digit can be any one of 0,2,4,6,8 hence 5 ways

Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)

=56

3 0
3 years ago
I need help with the following picture​
kolbaska11 [484]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
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