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Inga [223]
2 years ago
11

Given the function f(X)= |3x-7|, find the values of X that satisfy the equation f(X) = 4

Mathematics
1 answer:
Kay [80]2 years ago
5 0

Answer:

x = 1 or x = \frac{11}{3}

Step-by-step explanation:

The expression inside the absolute value function can be positive or negative

That is 3x - 7 = ± 4

There are 2 equations to solve

(1)

3x - 7 = 4 ( add 7 to both sides )

3x = 11 ( divide both sides by 3 )

x = \frac{11}{3}

(2)

3x - 7 = - 4 ( add 7 to both sides )

3x = 3 ( divide both sides by 3 )

x = 1


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Can two different numbers have the same absolute value? If yes, give an example. If no, explain why not
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Delicious77 [7]

Please, for clarity, use " ^ " to denote exponentiation:


Correct format: x^4*y*(4) = y*x^2*(13)

This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.


Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.

The question here is whether you can find this x^2 + 2xy + y^2 in your

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Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.


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