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Finger [1]
3 years ago
13

a 10kg box initially at rest is pulled 18 meters accros horizontal, frictionless sutface by a 40 n what is the block's final vel

ocity over the 18 meters?
Health
1 answer:
Gelneren [198K]3 years ago
5 0
<h2>Answer</h2>

Final Velocity = 144 m/s

<h2>Explanation</h2>

Given that,

<em>mass of the box = 10kg</em>

<em>distance the box travelled = 18m</em>

<em>initial speed = 0 m/s</em>

<em>Force = 40N</em>

<em />

Force = mass x acceleration

40N = 10 x acceleration

acceleration = 40/10

acceleration = 4m/s²

<h3> Formula for final speed </h3><h2> v - u = 2 as</h2>

<em>where u = initial velocity</em>

<em>            v = final velocity</em>

<em>            a = acceleration</em>

<em>             s = distance</em>

v - 0 = 2(4)(18)

v = 2(4)(18)

v = 144 m/s

So the block's final velocity = 144m/s

<h2 /><h2 />
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