A month of the year is chosen at random. What is the probability that the month starts with the letter J or the letter M?

2 answers:

4 0

5/12 because there is that about of months that either have J or M and it’s out of the amount of months there is

3 0

Answer:

5/12

Step-by-step explanation:

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oksian1 [2.3K]

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Step-by-step explanation:

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3 years ago

andrew-mc [135]

The answer is

y = (-x) - 1

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3 years ago

Katen [24]

You can give me the choices, are there even any?

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3 years ago

Dmitrij [34]

.1 Simplify: 5n(2n3+n2+8)+n(4-n).

Solution:

5n(2n3+n2+8)+n(4-n).

= 5n × 2n3 + 5n × n2 + 5n × 8 + n × 4 - n × n.

= 10n4 + 5n3 + 40n + 4n – n2.

= 10n4 + 5n3 + 44n – n2.

= 10n4 + 5n3 – n2 + 44n.

Answer: 10n4 + 5n3 – n2 + 44n

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3 years ago

RideAnS [48]

The answer would be C because it’s the only fraction that does not equal 0.4

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3 years ago