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cricket20 [7]
3 years ago
9

A rectangle has a height of 6k3 and a width of 2k2 + 4k +5.

Mathematics
1 answer:
Trava [24]3 years ago
5 0

Answer: 12k^5+24k^4+30k^3

Step-by-step explanation:

Given : The height of the rectangle = 6k^3

The width of the rectangle = 2k^2+4k+5

Formula : Area = height x width

Therefore , the area of triangle in terms of polynomial will be :

6k^3\times( 2k^2+4k+5)\\\\= 6k^3(2k^2)+6k^3(4k)+6k^3(5)\ \ [\text{Using Distributive property}]\\\\=12k^{3+2}+24k^{3+1}+30k^3\ \ [\text{Using exponents rule}:\ a^n\times a^m=a^{n+m}]\\\\=12k^5+24k^4+30k^3

Hence, the area of the entire rectangle =12k^5+24k^4+30k^3

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Step-by-step explanation:

1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...

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This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.

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