3 years ago

Factor 16x2 + 40x + 25

1 answer:

3 0

The answer is c to your question

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oksian1 [2.3K]

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zheka24 [161]

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Aleonysh [2.5K]

Answer:

bro no one cares

Step-by-step explanation:

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2 years ago

DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

$\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}$

$d\bar{c}=\left ( -6x^{-2}+\frac{1}{6}\right )dx$

Now, integrating both sides

$\int d\bar{c}=\int \left ( -6x^{-2}+\frac{1}{6}\right )dx$

$\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1$

$\bar{c}=6x^{-1}+\frac{1}{6}x+k_1$

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3 years ago

snow_tiger [21]

Positive if I looked at graph correctly

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2 years ago