Answer:
The cross is as follows:
P: D/d × d/d
Explanation:
Half of the F1 progeny are mutant. The mutation results in 3 cotyledons is dominant and the original mutant is heterozygous.
If D denotes the mutant allele and d denotes the wild type allele.
The cross is as follows:
P: D/d × d/d
F1 denotes D/d three cotyledons
d/d denote two cotyledons
Answer:
tertiary; quaternary
Explanation:
The orientation of all the atoms of a protein in three dimensions represents its tertiary structure. It includes the folding of the polypeptide chains in a way that brings are far apart amino acids of its secondary structure close together. Various segments of a polypeptide chain interact to form tertiary structures and these segments are held together by different kinds of weak interactions.
However, disulfide cross-links between the segments of polypeptide chains also stabilize the tertiary structure of some proteins. Likewise, disulfide bonds also hold the protein subunits of some proteins together and thereby, contribute to the quaternary structure. For example, two light chains of an antibody are joined together by disulfide bonds.
Answer:
The remaining ADP is at lower energy state.
Explanation:
ATP contain three phisphate bond. These phosphate groups form phosphodiester bond. Hydrolysis of each phosphate bond release about 7.3 Kcal of energy and one ADP. Now this ADP contain only one bond between phosphate group.
Result:
It is clered from the discussion that ADP is at lower energy level as compared to ATP due to less bond between phosphate group.
