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mafiozo [28]
3 years ago
6

Prove that the two circles shown below are similar.

Mathematics
2 answers:
cestrela7 [59]3 years ago
6 0

Answer:

Well we need to find the area of circles B and D

We’ll use the following formula,

\pi r^2

B)

The radius of the

is circle is 4 units,

so we plug 4 into \pi r^2.

pi(4)^2

4*4 =16

16 * pi = 50.2654824574

The answer is 50 rounded to the nearest whole number.

D)

The radius is 2,

pi(2)^2

2*2 = 4

pi * 4 = 12.5663706144

Or 13 Rounded to the nearest whole number.

So now we do 50 ÷ 13 = 3.84615384615

Which is about 4 rounded to the nearest whole number.

<em>Thus,</em>

<em>The two circles are similar just that circle D is multiplied by a scale factor of 4 to get circle B</em>

jolli1 [7]3 years ago
5 0

Answer:

They have a scale factor of 2

They are both the same shape

The big circle has a radius of 4 and the small circle has a radius of 2. You divide the bigger circle by the smaller circle. 4/2=2

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Faiza, Krish and Joe start cycling around the park from the same point at the same time. Faiza circles the park in 60 seconds, K
pishuonlain [190]

Answer:

The time at which they will all meet at a place together is 350 minutes

Step-by-step explanation:

The time it takes Faiza to cycle the park = 60 seconds

The time it takes Krish to cycle the park = 14 seconds

The time it takes Joe to cycle the park = 25 seconds

Therefore, the time they will all meet at a place together is given by their Lowest Common Multiple as follows;

LCM = 60 × 14 × 25 = 21,000 seconds

Therefore, the time at which they will all meet at a place together in minutes = 21000 seconds/(60)×minute/second = 350 minutes

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3 years ago
If -x &lt; -y, then all of the following are true except?
Marysya12 [62]

Answer:

b, c, d are all false

Step-by-step explanation:

Let x=4, y=2. The given statement says ...

... -4 < -2 . . . . . a true statement.

Now, let's look at the answer choices.

... a. -4 < -2 . . . . true

... b. 2(4) < 2(2) . . . . false

... c. 4 +2 < 2 +2 . . . . false

... d. 4/2 < 2/2 . . . . false

Then "a" is true, and "b", "c", and "d" are false.

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3 years ago
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andriy [413]

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A pair of opposite rays would be.
vodomira [7]

Answer:

Option (4)

Step-by-step explanation:

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Therefore, from the picture attached,

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3 years ago
How can I tell, when doing synthetic division, if the binomial is<br> a FACTOR of the dividend?
Alecsey [184]

If you get 0 as the last value in the bottom row, then the binomial is a factor of the dividend.

Let's say the binomial is of the form (x-k) and it multiplies with some other polynomial q(x) to get p(x), so,

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If you plug in x = k, then,

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The input x = k leads to the output y = 0. Therefore, if (x-k) is a factor of p(x), then x = k is a root of p(x).

It turns out that the last value in the bottom row of a synthetic division table is the remainder after long division. By the remainder theorem, p(k) = r where r is the remainder after dividing p(x) by (x-k). If r = 0, then (x-k) is a factor, p(k) = 0, and x = k is a root.

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