Question

13. Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?

Answer 1

The frequency of RR is found by squaring the frequency of R. The answer is about .72 or 72 %

Answer 2

Answer:

Frequency of the RR genotype $= 72.25$

Explanation:

Here Hardy Weinberg's equation would be applicable as it is assumed that evolution is not occurring.

As per Hardy Weinberg's equation, the frequency of recessive allele is represented by "q"

Here, $q = 0.15$

And the frequency of dominant allele is represented by "p"

Here, $p = 0.85$

So the frequency of the RR genotype, i,e the homozygous dominant genotype is represented by

$p^{2} = 0.85^2\\= 0.7225\\= 72.25$