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r-ruslan [8.4K]
3 years ago
11

The modern atomic model is sometimes called the ________, or quantum mechanics model.

Physics
2 answers:
aev [14]3 years ago
6 0

electron cloud just took the quiz

Sav [38]3 years ago
3 0
A. Bohr
It's the Answer to your Question
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An object initially at rest experiences an acceleration of 9.8 m/s2 how much time will it take it to achieve a velocity of 58 m/
Ber [7]

Answer:

The time required by object to achieve velocity 58 m/s is 5.918 second.

Given:

acceleration = 9.8 \frac{m}{s^{2} }

Initial velocity = 0 m/s

final velocity = 58 m/s

To find:

Time required by object = ?

Formula used:

According to first equation of motion is given by,

v = u + at

Where, v = final velocity

u = initial velocity = 0 (Given The particle is at rest initially)

a = acceleration

t = time

Solution:

According to first equation of motion is given by,

v = u + at

Where, v = final velocity

u = initial velocity = 0 (Given The particle is at rest initially)

a = acceleration

t = time

58 = 0 + 9.8 (t)

t = \frac{58}{9.8}

t = 5.918 s

The time required by object to achieve velocity 58 m/s is 5.918 second.



8 0
4 years ago
Matter can exist in hw many states​
Mariulka [41]

Answer:

Matter can exist in four different states: solids, liquids, gases and plasma.

Explanation:

Hope this helps :)

4 0
3 years ago
Plants absorb WHAT from the atmosphere and release WHAT to the atmosphere.
makvit [3.9K]
Plants absorb water and release o2
6 0
3 years ago
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Examine the scenario.
frutty [35]
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6 0
3 years ago
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You illuminate a slit with a width of 71.7 μm with a light of wavelength 737 nm and observe the resulting diffraction pattern on
miskamm [114]

To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

sin(\theta_{min}) = \frac{m\lambda}{D}

Here,

m = Order of the fringes

D = Distance between slits

\lambda = Wavelength

Replacing with our values we have,

sin(\theta_{min}) = \frac{(1)(737*10^{-9})}{71.7*10^{-6}m}

sin(\theta_{min}) = 0.01028

Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then

Y=Lsin\theta

Y  =2.27*0.01028

Y =0.0233m

Thus the width of the central maximum is

W=2Y=2*0.0233

W = 0.0466m

Therefore the widht is 0.466m

6 0
4 years ago
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