Answer:
The magnitude of the electric field are
and 
Explanation:
Given that,
Radius of inner shell = 11.0 cm
Radius of outer shell = 14.0 cm
Charge on inner shell 
Charge on outer shell 
Suppose, at r = 11.5 cm and at r = 20.5 cm
We need to calculate the magnitude of the electric field at r = 11.5 cm
Using formula of electric field

Where, q = charge
k = constant
r = distance
Put the value into the formula


The total charge enclosed by a radial distance 20.5 cm
The total charge is

Put the value into the formula


We need to calculate the magnitude of the electric field at r = 20.5 cm
Using formula of electric field

Put the value into the formula


Hence, The magnitude of the electric field are
and 
Answer: D.
Explanation: Just took the quiz.
Answer:
metal and non-metal
Explanation:
Ionic bonds are formed when a metal loses electrons and a non-metal gains said electrons.
Answer:
v = 98.75 km/h
Explanation:
Given,
The distance driver travels towards the east, d₁ = 135 km
The time period of the travel, t₁ = 1.5 h
The halting time, tₓ = 46 minutes
The distance driver travels towards the east, d₂ = 215 km
The time period of the travel, t₁ = 2 h
The average speed of the vehicle before stopping
v₁ = d₁/t₁
= 135/1.5
= 90 km/h
The average speed of vehicle after stopping
v₂ = d₂/t₂
= 215/2
= 107.5 km/h
The total average velocity of the driver
v = (v₁ +v₂) /2
= (90 + 107.5)/2
= 98.75 km/h
Hence, the average velocity of the driver, v = 98.75 km/h