Answer:
The velocity of Mosquito with respect to earth will be 0.302m/s
Explanation:
V(ma) = 1.10 m/s, east Velocity of mosquito with respect to air
V(ae) = 1.4 m/s at 35° Velocity of air with respect to Earth in west of south direction.
Velocity of Mosquito with respect to earth will be
V(me) = V(ma) + V(ae)
We need to find the mosquito’s speed with respect to Earth in the x direction.
V(x, me) = V(x, ma) + V(x, ae) = V(ma) + V(ae)(cos theta(ae) )
Angle (ae) = –90.0° − 35°=−125°
V(x, me) = 1.10 + (1.4)Cos(-125)
= 1.10 + 1.4(-0.57)
= 1.10 -0.798
= 0.302
So the velocity of Mosquito with respect to earth will be 0.302m/s
<span>The eastern margin is a convergent boundary subduction zone under the South American Plate and the Andes Mountains, forming the Peru–Chile Trench. The southern side is a divergent boundary with the Antarctic Plate, the Chile Rise, where seafloor spreading permits magma to rise.</span>
<span>Convection is a process of heat transfer between a surface and a moving fluid. It occurs when the air has a lower temperature than the body, and the body transfers heat through contact with the cold air around it. Air heating causes it to rise. The increase in temperature affects the convection process, since as the warm air rises, the cold air takes its place, thus completing its convection cycle.
Example: Wind</span>
*Graph is attached with the answer*
Answer:
Total distance traveled by the car is 40 m
Explanation:
It can be seen from the graph that for the first 4 second car is moving with uniform acceleration and for next 2 second it has constant velocity
So, we solved this question in 2 parts
Part 1:
initial velocity = v₁ = 0 m/s
final velocity = v₂ = 10 m/s
time = t = 4 s
acceleration = a = (v₂ - v₁)/t
a = 10/4 = 2.5 m/s²
Using 3rd equation of motion
2as = v₂² - v₁²
2(2.5)s = 10²
s₁ = 100/5
s₁ = 20 m
Part 2:
s₂ = v₂t
s₂ = 10 × 2
s₂ = 20 m
Total distance = S = s₁ + s₂
= 20 + 20
S = 40 m
