An object initially at rest experiences an acceleration of 9.8 m/s2 how much time will it take it to achieve a velocity of 58 m/
1 answer:
Answer:
The time required by object to achieve velocity 58 m/s is 5.918 second.
Given:
acceleration = 9.8
Initial velocity = 0 m/s
final velocity = 58 m/s
To find:
Time required by object = ?
Formula used:
According to first equation of motion is given by,
v = u + at
Where, v = final velocity
u = initial velocity = 0 (Given The particle is at rest initially)
a = acceleration
t = time
Solution:
According to first equation of motion is given by,
v = u + at
Where, v = final velocity
u = initial velocity = 0 (Given The particle is at rest initially)
a = acceleration
t = time
58 = 0 + 9.8 (t)
t =
t = 5.918 s
The time required by object to achieve velocity 58 m/s is 5.918 second.
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Answer:
Explanation:
Let the mass of bullet is m, initial velocity of bullet is vi and c be the specific heat of the bullet.
Kinetic energy, K = 1/2 mvi^2
According to the question, 50% of the kinetic energy is equal to the heat energy absorbed by the bullet.
50% of K = mass of bullet x specific heat x rise in temperature
1/4 mvi^2 = m x c x ΔT
Answer:
(a) 1.5 second
(b) 0.56 m
Explanation:
Pendulum makes 120 oscillations in 3 min that means in 180 seconds
time taken by the pendulum to complete one oscillation is called time period.
(a) So, the time period is 180 / 120 = 1.5 second
T = 1.5 second
Thus, the time period of the pendulum is 1.5 second.
(b) g = 9.8 m/s^2
The formula for the time period is given by
Where, L be the length of pendulum
L = 0.56 m
Thus, the length of the pendulum is 0.56 m .