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garri49 [273]
3 years ago
10

Distance between (0,2) and (0,4)

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0
D= √(x sub2 - x sub1)^2 + (y sub2 - ysub1)

D= √(0-0)^2 + (4-2)^2

D= √0^2 + 2^2

D= √0 + 4

D= √4

D = 2
Lorico [155]3 years ago
5 0
There are many ways to do this, I prefer the distance formula it looks like this:
\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
We are given 2 pairs of coordinates: (0,2) and (0,4) 
0=x1
2=y1
0=x2
4=y2
We take the numbers and sub in the values above in place of the variables:
  \sqrt{(0-0)^2+(4-2)^2}
Simplfy it: 
\sqrt{(0)^2+(2)^2}
0^2=0
2^2=4
We are left with :
\sqrt{4}
\sqrt{4} =2
Final answer: 2 
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Anna [14]

Answer:

The florist can make 11 regular bouquets and 21 mini bouquets

Step-by-step explanation:

The number of roses the florist has = 118 roses

The number of peonies the florist has = 226 peonies

The number of roses in each regular bouquet = 5 roses

The number of peonies in each regular bouquet = 11 peonies

The number of roses in each mini bouquet = 3 roses

The number of peonies in each mini bouquet = 5 peonies

1. The equation that gives the total number of roses to be used in both kinds of bouquet is given as follows;

Let r represent the number of regular bouquet the florist can make and let m represent the number of mini bouquet the florist can make, we have;

5·r + 3·m = 118...(1)

2. Similarly, we have;

11·r + 5·m  = 226...(2)

Making m the subject of the formula of both equations, and equating both values of m to find a common solution, we have;

m = (118 - 5·r)/3

m = (226 - 11·r)/5

(118 - 5·r)/3 = (226 - 11·r)/5

5 × (118 - 5·r) = 3 × (226 - 11·r)

590 - 25·r = 678 - 33·r

33·r - 25·r = 678 - 590 = 88

8·r = 88

r = 88/8 = 11

r = 11

The number of regular bouquet the florist can make = r = 11

m = (118 - 5·r)/3 = (118 - 5×11)/3 = 21

m = 21

The number of mini bouquet the florist can make = m = 21

The number of regular bouquet the florist can make = 11 bouquets

The number of mini bouquet the florist can make = 21 bouquets.

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