The complete question in the attached figure
we know that
in the triangle BDC
cos alfa=3/y----------> equation 1
sin alfa=x/y----------> equation 2
in the triangle ABD
cos alfa=4/5--------> equation 3
sin alfa=3/5---------> equation 4
then
Equal equation 1 and 3
3/y=4/5---------> y/3=5/4----------> y=15/4
Equal equation 2 and 4
x/y=3/5-------> x=3*y/5------------> 3*15/(4*5)-----> x=9/4
the answer is
<span>x=9/4 y=15/4</span>
The most simplified answer is the greatest factor being six. Divide both by six and six is on the outside of parentheses to be equivalent making the answer 6(2s+18r) or -6(-2s-18r) if you used negatives as I would jot down negative and positive
Answer and explanation:
Surface area of a rectangle = length * width
Surface area of a square = a² where a is length of a side
To find total surface area of the the five pieces of paper, we add up all the areas of all the shapes
Given that length of rectangle =3.5
And width = 2
Area of rectangle =3.5*2=7
Area of 3 rectangles given they are all equal = 7*3=21
Since width of rectangle equal to width of square and all sides of square are equal
Area of square = 2 *2 =4
Area of the two squares =4*2=8
Total surface area of the five plane shapes = 21+8= 29
Answer:
3/4
Area of the small triangle/Area of larger triangle=3/4
Area of the small triangle/Area of larger triangle=(1/2×base of small triangle×length)/(1/2×base of larger triangle×height)
3/4=(1/2×base of small triangle×height)/(1/2×base of larger triangle×height)
Since the length of the triangle are equal the base ratio of the two triangles is the same as area ratio.