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monitta
3 years ago
10

True or False?In Exercise,determine whether the statement is true or false given that f(x) = In x.if it is false,explain why or

given an example that shows it is false.
f(x - 2) = f(x) - f(2), x > 2
Mathematics
1 answer:
kompoz [17]3 years ago
6 0

Answer:

The given statement is false.

Step-by-step explanation:

We are given the following in the question:

f(x) = \text{In } x

The given statement is

f(x - 2) = f(x) - f(2), x > 2

Putting the values on the right side of the given statement

f(x-2)\\=\text{ln }(x-2) \neq \text{ln }x - \text{ln }2

Thus, the given statement is false.

This can be explained with the help of an example:

For x = 3

f(x-2) = f(3-2) = f(1)\\=\text{ln }1 = 0\\f(x)-f(2)\\=\text{ln }3-\text{ln }2 \\=0.4054

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Help!!! Quick!!! Plzzzzz!!!
max2010maxim [7]

Answer:

x = -8

y = 9

Step-by-step explanation:

to solve this expression using simultaneous equation, we would say let

y =9............................................. equation 1

 6x + 5y =-3............................................equation 2

substitute equation 1 into equation 2

-3 = 6x + 5y............................................equation 2

6x + 5(9) = -3

6x + 45 = -3

collect the like terms

6x = -3-45

6x = -48

divide both sides by the coefficient of x which is 6

6x/6 = -48/6

x = -8

therefore y = 9

x = -8

4 0
3 years ago
Allen is buying a video game that originally costs $49. He has a 10%-off
Annette [7]
The total amount Allen will need to pay for the video game is $48.96 as 49-0.1+0.06=48.96
7 0
3 years ago
How do i factor (10x^2-25x-15)
Otrada [13]
5(2x^2 - 5x - 3) = 5(2x + 1)(x - 3)

hope this helps :)
4 0
3 years ago
This is a "water tank" calculus problem that I've been working on and I would really appreciate it if someone could look at my w
Sedaia [141]
Part A

Everything looks good but line 4. You need to put all of the "2h" in parenthesis so the teacher will know you are squaring all of 2h. As you have it right now, you are saying "only square the h, not the 2". Be careful as silly mistakes like this will often cost you points. 

============================================================

Part B

It looks like you have the right answer. Though you'll need to use parenthesis to ensure that all of "75t/(2pi)" is under the cube root. I'm assuming you made a typo or forgot to put the parenthesis. 

dh/dt = (25)/(2pi*h^2)
2pi*h^2*dh = 25*dt
int[ 2pi*h^2*dh ] = int[ 25*dt ] ... applying integral to both sides
(2/3)pi*h^3 = 25t + C
2pi*h^3 = 3(25t + C)
h^3 = (3(25t + C))/(2pi)
h^3 = (75t + 3C)/(2pi)
h^3 = (75t + C)/(2pi)
h = [ (75t + C)/(2pi) ]^(1/3)

Plug in the initial conditions. If the volume is V = 0 then the height is h = 0 at time t = 0
0 = [ (75(0) + C)/(2pi) ]^(1/3)
0 = [ (0 + C)/(2pi) ]^(1/3)
0 = [ (C)/(2pi) ]^(1/3)
0^3 =  (C)/(2pi)
0 = C/(2pi)
C/(2pi) = 0
C = 0*2pi
C = 0 

Therefore the h(t) function is...
h(t) = [ (75t + C)/(2pi) ]^(1/3)
h(t) = [ (75t + 0)/(2pi) ]^(1/3)
h(t) = [ (75t)/(2pi) ]^(1/3)

Answer:
h(t) = [ (75t)/(2pi) ]^(1/3)

============================================================

Part C

Your answer is correct. 
Below is an alternative way to find the same answer

--------------------------------------

Plug in the given height; solve for t
h(t) = [ (75t)/(2pi) ]^(1/3)
8 = [ (75t)/(2pi) ]^(1/3)
8^3 = (75t)/(2pi)
512 = (75t)/(2pi)
(75t)/(2pi) = 512
75t = 512*2pi
75t = 1024pi
t = 1024pi/75
At this time value, the height of the water is 8 feet

Set up the radius r(t) function 
r = 2*h
r = 2*h(t)
r = 2*[ (75t)/(2pi) ]^(1/3) .... using the answer from part B

Differentiate that r(t) function with respect to t
r = 2*[ (75t)/(2pi) ]^(1/3)
dr/dt = 2*(1/3)*[ (75t)/(2pi) ]^(1/3-1)*d/dt[(75t)/(2pi)] 
dr/dt = (2/3)*[ (75t)/(2pi) ]^(-2/3)*(75/(2pi))
dr/dt = (2/3)*(75/(2pi))*[ (75t)/(2pi) ]^(-2/3)
dr/dt = (25/pi)*[ (75t)/(2pi) ]^(-2/3)

Plug in t = 1024pi/75 found earlier above
dr/dt = (25/pi)*[ (75t)/(2pi) ]^(-2/3)
dr/dt = (25/pi)*[ (75(1024pi/75))/(2pi) ]^(-2/3)
dr/dt = (25/pi)*[ (1024pi)/(2pi) ]^(-2/3)
dr/dt = (25/pi)*(1/64)
dr/dt = 25/(64pi)
getting the same answer as before

----------------------------

Thinking back as I finish up, your method is definitely shorter and more efficient. So I prefer your method, which is effectively this:
r = 2h, dr/dh = 2
dh/dt = (25)/(2pi*h^2) ... from part A
dr/dt = dr/dh*dh/dt ... chain rule
dr/dt = 2*((25)/(2pi*h^2))
dr/dt = ((25)/(pi*h^2))
dr/dt = ((25)/(pi*8^2)) ... plugging in h = 8
dr/dt = (25)/(64pi)
which is what you stated in your screenshot (though I added on the line dr/dt = dr/dh*dh/dt to show the chain rule in action)
8 0
3 years ago
The function below models the correlation between the number of hours a plant is kept in sunlight (x) and the height (y), in mm,
Vsevolod [243]
<span>The correct answer is The original height of the plant was 4 mm.</span>
6 0
3 years ago
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