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monitta
3 years ago
10

True or False?In Exercise,determine whether the statement is true or false given that f(x) = In x.if it is false,explain why or

given an example that shows it is false.
f(x - 2) = f(x) - f(2), x > 2
Mathematics
1 answer:
kompoz [17]3 years ago
6 0

Answer:

The given statement is false.

Step-by-step explanation:

We are given the following in the question:

f(x) = \text{In } x

The given statement is

f(x - 2) = f(x) - f(2), x > 2

Putting the values on the right side of the given statement

f(x-2)\\=\text{ln }(x-2) \neq \text{ln }x - \text{ln }2

Thus, the given statement is false.

This can be explained with the help of an example:

For x = 3

f(x-2) = f(3-2) = f(1)\\=\text{ln }1 = 0\\f(x)-f(2)\\=\text{ln }3-\text{ln }2 \\=0.4054

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10- 3/4z = 8<br><br> Somebody, please help me! I don't get this!
gizmo_the_mogwai [7]

Answer:

z = 8/3

Step-by-step explanation:

10- 3/4z = 8

Subtract 10 from each side

10-10- 3/4z = 8-10

-3/4z = -2

Multiply each side by -4/3

-3/4z * -4/3 = -2 *4/3

z = 8/3

6 0
2 years ago
Which represents a perfect cube? 6 times 6 times 6 6 + 6 + 6 3 times 3 times 3 times 3 3 + 3 + 3 + 3 + 3
mojhsa [17]

Answer:

6 times 6 times 6

Step-by-step explanation:

6 x 6 = 6²

Therefore 6 x 6 x 6 = 6³

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3 years ago
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3 years ago
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A store sells candles.
maria [59]

Answer:

25%

Step-by-step explanation:

If you start at 45% and it reduces by 20% you are just doing 45-20 which equals 25. (Please let me know if im wrong)

7 0
3 years ago
A bird has a mass of 26 g and perches in the middle of a stretched telephone line. (a) Show that the tension in the line can be
Semmy [17]

Answer:

a) is demonstrated below, b) T=1.462N, c) T=14.6N

Step-by-step explanation:

a) Refer to the attached diagram.

Since the bird is standing in the middle of the line and each half is a straight line, Ta=Tb, so we will call the tension T=Ta=Tb and Tay=Tby

By trigonometry Tay=Ta·Sinθ

Since the system is in equilibrium W=Tay+Tby then:

W=2·Tay=2·Ta·Sinθ=2·T·Sinθ

Since W=mg, being m the mass of the bird and g, gravity:

mg=2TSin\theta

Isolating T, we demonstrate that

T=\frac{mg}{2Sin\theta}

b) Replacing θ=5º, m=0.026kg and g=9.8m/s² in the last equation, we can get the tension in Newtons:

T=\frac{0.026*9.8}{2Sin5}=1.462N

c) With θ=0.5º

T=\frac{0.026*9.8}{2Sin0.5}=14.6N

7 0
3 years ago
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