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Kryger [21]
4 years ago
5

An artist is hired to create an art display for the interior of a city building. The display is to span a total width of 10 yd .

The artist decides to cover this space with equally sized portraits placed side-by-side in a horizontal line with no gaps. Each portrait has a width of 45 in . How many portraits will be used in the display
Mathematics
1 answer:
lesya692 [45]4 years ago
7 0

Answer:

8 portraits are going to be used in the display.

Step-by-step explanation:

This problem can be solved as a rule of three problem.

Each yd has 36 inches.

The display is to span a total width of 10 yd. So it is a total width of 360 inches.

Each portrait has a width of 45 in. How many portraits can there be?

1 portrait - 45 in

x portraits - 360 in

45x = 360

x = 8

8 portraits are going to be used in the display.

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The marine needs 14 boats for the 42 people registered for a boat race. How many boats will they need for 6 people?​
Degger [83]

Answer:

2

Step-by-step explanation:

We can write a proportion to determine

42 people          6 people

---------------- = ----------------

14 boats                x boats

Using cross products

42x = 6*14

42x =84

Divide each side by 42

42x/42 = 84/42

x = 2

They will need 2 boats

5 0
3 years ago
pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base
kaheart [24]

Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

__

We expect your answer is supposed to be Step 4.

7 0
4 years ago
I will give Brainliest !
Sidana [21]

Answer:i believe it’s A

Step-by-step explanation:

4,5,3 are almost the same and almost the same rotation just letters are different

3 0
3 years ago
Please help!!! thank you
Dahasolnce [82]
That’s the answer because I couldn’t type it out! Hope it helped!

8 0
3 years ago
Read 2 more answers
Solve the system of equations using the addition method 2a+3b=-1 ; 3a+5b=-2
Alexeev081 [22]

Answer:

Then, a=-1 and b=-1

Step-by-step explanation:

We need to solve the following system of equations using the adition method:

2a+3b=-1       (i)

3a+5b=-2      (ii)

First, we multiply the equation (i) by -3 and the equation (ii) by 2, so we get:

-6a-9b=3

6a+10b=-4

Adding the two equations we have:

-6a-9b=3

6a+10b=-4

--------------------------

 0  + b = -1

Then b=-1. Now, let's substitute the value of b into equation (i):

2a+3b=-1

2a + 3(-1) = -1

2a -3 = -1

2a = 2

a = 1

Then, a=-1 and b=-1

3 0
4 years ago
Read 2 more answers
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