Answer:
You must survey 784 air passengers.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Assume that nothing is known about the percentage of passengers who prefer aisle seats.
This means that
, which is when the largest sample size will be needed.
Within 3.5 percentage points of the true population percentage.
We have to find n for which M = 0.035. So






You must survey 784 air passengers.
The order is 1/6, 4/19, 1/2, 7/12, 7/12, and 2/3.
I think it's A.
The difference = x - 5, where x is Jamie's height.
Answers
remove the ( ) fast and then add the numbers that look the same.
(22+19b)+7
22+19b+7
22+7+19b
= 29+19b
18+(5+6m)
18+5+6m
= 23+6m
here u don't care about same or not same u just multiply or divide
11s(4)
= 44s
10y(7)
= 70y
(9+31+5)(7times5)times4)
(45)(35)4
(1575)4
= 6300