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3 years ago

If f(x) = 2x -1 and g(x) = x^2 what is the value of f(g(-3))? PLZ HELP WILL MARK BRAINLIEST

Mathematics

1 answer:

Arada [10]3 years ago

3 0

Answer:

f(g(-3))= 17.

Step-by-step explanation:

Start evaluating from the inside and work your way out. This means you start with (-3)²=9. Then go and plug that answer in to the equation f(x). f(9)=2(9)-1=17.

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What is the slope of the line that passes through the points (13,-8) and (-11,4)

pogonyaev

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

Find slope using the slope formula : $\frac{y2-y1}{x2-x1}$

Plug in the given points : $\frac{4- (-8)}{-11-13}$

Add the numbers : $\frac{12}{-11-13}$

Calculate the difference : $\frac{12}{-24}$

Reduce the fraction : - $\frac{1}{2}$

Solution : - $\frac{1}{2}$

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2 years ago

Which fraction is equivalent to -(3/4)?

Alekssandra [29.7K]

Answer:

I dont understand the context of the question but something eqqual to that would be -6/8

Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

Harrizon [31]

Answer:

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have points (1,6) and (2,2)

Slope is:

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2$

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11$

The equation of line will be:

$y=mx+b\\y=-2x+11$

Equation of the line that passes through the given point and is (a) parallel is: $\mathbf{y=-2x+11}$

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

$y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1$

The equation of line will be:

$y=mx+b\\y=\frac{1}{2}x+1$

Equation of the line that passes through the given point and is (b) perpendicular is: $\mathbf{y=\frac{1}{2}x+1}$

6 0

2 years ago