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Aleks [24]
4 years ago
7

Kamila has a rectangular lawn that measures 80 by 150 feet. She wants to lay gravel made from colored rock in a border, 6 feet w

ide, all around the lawn. Create a diagram that shows Kamila’s rectangular lawn and the gravel border. Assign variables to any unknown sides and label the diagram. Use your diagram to determine how many square feet of the gravel border will surround the lawn. Kamila decided that the depth of the gravel needs to be 2 inches. What is the total volume of gravel needed for the border? (Hint: dimensions must be in terms of the same unit before you can calculate the volume) D. A large bag of colored rock contains of a cubic yard and costs $30. What is the total cost of the rocks needed for the border? (Hint: the volume of the border must be in terms of a cubic yard before you can calculate the cost)
Mathematics
1 answer:
beks73 [17]4 years ago
7 0
A) Diagram

Below is a sketch of the recctangular lawn (the inside rectangle) and the gravel border.


  6 ft + 150 yards + 6 ft
-------------------------------
|                                    |
|     ---------------------      |
|     |                        |     |
|     |                        |     |   6 ft + 80 yard + 6 ft
|     |                        |     |
|      ---------------------     |
|                                    |
|------------------------------|

B) How many square feet of the gravel will surround the lawn?

Conversion: 1 yard = 3 feet

=> 80 yard = 80*3 feet = 240 feet

=> 150 yard = 150 * 3 feet = 450 feet

Area of the external rectangle = (6 ft + 240 ft + 6 ft) (6 ft + 450 ft + 6 ft) = 252 ft * 462 ft = 116,424 ft^2

Area of the internal rectangle = 240 ft * 450 ft = 108,000 ft^2

Area of the gravel border = 116,424 ft^2 - 108,000 ft^2 = 8424 ft^2

answer: 8424 ft^2

C) volume

volume = area of the base * depth

2 inches = 2/12 ft = 1/6 ft

=> volume = 8424 ft^2 * 1/6 ft = 1404 ft^3

answer: 1404 ft^3

C) cost

1 yard^3 = $ 30

1yard ^3 = (3 feet)^3 = 27 ft^3

=> cost = $ 30 / 27 ft^3

=> 1404 ft^3 * $30 / 27 ft^3 = $ 1560

answer: $ 1560
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Marty and Ethan both wrote a function, but in different ways.
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Answer:

Marty's with a slope of 1/3

Step-by-step explanation:

The functions Marty and Ethan wrote are analyzed the find the slope of each of the function

The equation Marty wrote is presented here as follows;

y + 3 = \dfrac{1}{3} \cdot\left (x + 9 \right)

Marty's equation can be written in slope and intercept form, <em>y = m·x + c</em>, as follows;

y  = \dfrac{1}{3} \cdot\left (x + 9 \right) - 3

y  = \dfrac{1}{3} \cdot x + \dfrac{9}{3}  \right) - 3 = \dfrac{1}{3} \cdot x + 0

y = \dfrac{1}{3} \cdot x

By comparison, the slope of the function, m = 1/3

\therefore \ the \ slope \ of \ Marty's \ function, \   y + 3 = \dfrac{1}{3} \cdot\left (x + 9 \right), \ m =\dfrac{1}{3}

Marty's function has a slope of m = 1/3

Ethan has the following two column table;

\begin{array}{rl}x&y\\-4&9.2\\-2&9.6\\0&10\\2&10.4\end{array}

The slope, <em>m,</em> of the data in the above table is given as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Taking any two points, (x₁, y₁) = (-4, 9.2), and (x₂, y₂) = (2, 10.4), we get;

Slope, \, m =\dfrac{10.4-9.2}{2-(-4)} = \dfrac{1.2}{6}  = \dfrac{1}{5}

Ethan's function has a slope of m = 1/5

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Marty's slope of 1/3 is larger, given that 1/3 > 1/5.

7 0
3 years ago
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
vladimir1956 [14]

Answer:

a) P(X ≤ 2) = 0.87

b)  P(X ≥ 5) = 0.01

c) P(1 ≤ X ≤ 4) = 0.71

d) P ( X = 0 ) = 0.28

e) σ(X) = 1.09 , E(X) = 1.25

Step-by-step explanation:

Given:

- Let X = the number of defective boards in a random sample of size n = 25, so X ~ Bin(25, 0.05)

Where, n = 25 and p = 0.05

Find:

(a) Determine P(X ≤ 2).(b) Determine P(X ≥ 5).(c) Determine P(1 ≤ X ≤ 4).(d) What is the probability that none of the 25 boards is defective?(e) Calculate the expected value and standard deviation of X.

Solution:

- The probability mass function for a binomial distribution is given by:

                         P ( X = x ) = nCr * (p)^r * ( 1 - p )^(n-r)

a) P(X ≤ 2):

                         P(X ≤ 2) = P ( X = 0 ) + P ( X = 1 ) + P ( X = 2 )

                         = (0.95)^25 + 25*0.05*0.95^24 + 25C2*0.05^2*0.95^23

                         = 0.87

b) P(X ≥ 5):

            P(X ≥ 5) = 1 - [P ( X = 0 ) + P ( X = 1 ) + P ( X = 2 ) + P ( X = 3 ) + P(X=4)

            = 1 - [ 0.87 + 25C3*0.05^3*0.95^22 + 25C4*0.05^4*0.95^21]

            = 1 - 0.98994

            = 0.01

c) P(1 ≤ X ≤ 4):

            P(1 ≤ X ≤ 4) = P ( X = 1 ) + P ( X = 2 ) + P ( X = 3 ) + P(X=4)

            = ( 0.87 - 0.95^25) + 0.11994

           = 0.71

d) P( X = 0 )

            P ( X = 0 ) = 0.95^25 = 0.28

e) E(X) & σ(X):

            E(X) = n*p

            E(X) = 25*0.05 = 1.25

            σ(X) = sqrt ( Var (X) )

            σ(X) = sqrt ( n*p*(1-p) ) = sqrt ( 25*0.05*0.95 )

            σ(X) = 1.09

4 0
3 years ago
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