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exis [7]
3 years ago
11

The skip interval in systematic random sampling is computed by dividing the number of potential sampling units on the list by th

e desired sample size .
O True
O False
Mathematics
1 answer:
nydimaria [60]3 years ago
6 0

Answer:

True

Step-by-step explanation:

The skip interval in systematic random sampling is computed by dividing the number of potential sampling units on the list by the desired sample size .

Systematic sampling is a type of probability sampling method in which sample members from a larger population are selected according to a random starting point but with a fixed, periodic interval (the sampling interval).

Sampling interval is calculated by dividing the population size by the desired sample size

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Inessa05 [86]

Step-by-step explanation:

7.2 / (-8.1) / (-3.7) = Positive

A = (-7.2) / (-8.1) / (-3.7) = Negative

B = (-7.2) / (8.1) / (3.7) = Negative

Hence the answer is C, none of the above.

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Answer:

<h2>(h + k)(2) = 5</h2>

Step-by-step explanation:

(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5

\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5

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