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sweet-ann [11.9K]
3 years ago
15

Solve the expression using pemdas (4+5)÷3×4​

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0

1) you add the variables in the bracket

(4+5)÷3×4

9÷3×4

2) you multiply 3 by 4

9÷3×4

9÷12

3) now you divide 9 by 12

9÷12

=0.75

LiRa [457]3 years ago
4 0
Your answer would be 12 because first your do your parenthesis then you divide and then you multiply.
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Find the probability of rolling a sum of 3.
yarga [219]

Answer:

robability formula is the ratio of number of favorable outcomes to the total number of possible outcomes. Measures the likelihood of an event in the following way: - If P(A) > P(B) then event A is more likely to occur than event B. - If P(A) = P(B) then events A and B are equally likely to occur.

Step-by-step explanation:

6 0
4 years ago
Part A: Factor x2y2 + 6xy2 + 8y2. Show your work. (4 points) Part B: Factor x2 + 8x + 16. Show your work. (3 points) Part C: Fac
skad [1K]

Answer:

Part A : y²(x + 2)(x + 4)

Part B: (x + 4) (x + 4)

Part C: (x + 4) (x - 4)

Step-by-step explanation:

Part A: Factor x²y²+ 6xy²+ 8y²

x²y²+ 6xy²+ 8y²

y² is very common across the quadratic equation , hence

= y² (x² + 6x + 8)

= (y²) (x² + 6x + 8)

= (y²) (x² + 2x +4x + 8)

= (y²) (x² + 2x)+(4x + 8)

= (y²) (x(x + 2)+ 4(x + 2))

= y²(x+2)(x+4)

Part B: Factor x² + 8x + 16

x² + 8x + 16

= x² + 4x + 4x + 16

= (x² + 4x) + (4x + 16)

= x( x + 4) + 4(x + 4)

= (x + 4) (x + 4)

Part C: Factor x² − 16

= x² − 16

= x² + 0x − 16

= x² + 4x - 4x - 16

= (x² + 4x) - (4x - 16)

= x (x + 4) - 4(x + 4)

= (x + 4) (x - 4)

6 0
3 years ago
A photo is printed on a 20-inch by 24-inch piece of paper. The photo covers 320 square inches and has a ubiform border. What is
zlopas [31]

Answer:2 in.

Step-by-step explanation:

Given

Dimension of photo frame is 20\ in.\times 24\ in.

If the photo cover an area of 320\ in.^2

Suppose x be the width of border

Therefore dimension of frame without border is

A'=(20-2x)(24-2x)

And A' must be equal to 320\ in.^2

So,

\Rightarrow (20-2x)(24-2x)=320

\Rightarrow (10-x)(12-x)=80

\Rightarrow 120-10x-12x+x^2=80

\Rightarrow x^2-22x+40=0

\Rightarrow x^2-20x-2x+40=0

\Rightarrow (x-2)(x-20)=0

Thus there are two values of x out of which x=20\ in. is not valid because it is not feasible

thus width of border is x=2\ in.

5 0
3 years ago
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Vaselesa [24]
Y= 4x+20

combine the cost of water and pretzels into 1
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