Ok so R=alfonso's rate
w=wind rate=4
d=rt
with wind rate is R+4
agaoins wind rate is R-4
with wind distance is 34
against is 18 miles
time is same
34=(r+4)t
18=(r-4)t
34=(r+4)t
divide both sides by (r+4)
34/(r+4)=t
18=(r-4)t
divide both sides by (r-4)
18/(r-4)=t
18/(r-4)=t
34/(r+4)=t
set equal to each other
18/(r-4)=34/(r+4)
multiply both sides by (r-4)(r+4)
18(r+4)=34(r-4)
distribute
18r+72=34r-136
subtract 18r from both sides
72=16r-136
add 136 to both sides
208=16r
divide both sides by 16
13mph
answer is 13mph with no wind
Let the width = x -12
the length = x
we have this area equation: x(x-12)=380.16
=>x^2-12x-380.16=0
=>(5x-132)(5x+72)=0
=>x= 132/5 and x= -72/5 (no)
=>The width of the poster is: 132/5 -12 =72/5 inches
Your solution will ASA... ∠M ≅ ∠Q ; MO ≅ QO ; ∠MON <span>≅ </span>∠QPO by vertical angles. So you have Angle - Side - Angle
The answer is D.
To find the mean you add all the numbers together and divide them by how many numbers there are.
22 + 37 + 49 + 15 + 72 = 195
195/5 = 39
Therefore, the answer is 39.
Answer:
5 tens and 8 ones gives 58
Step-by-step explanation:
We have to describe 58 as a sum of tens and ones
We know that first digit from the right is the ones place
Second digit is the tens place
Hence, 5 tens and 8 ones gives 58
Also, we can see that
10+10+10+10+10=50 (5 tens)
and 1+1+1+1+1+1+1+1=8 (8 ones)
on adding both we get 58
Hence, 5 tens and 8 ones gives 58
