2 years ago

Determine if the following system of equations has no solutions ......................

Mathematics

1 answer:

topjm [15]2 years ago

8 0

Answer:

No solutions

Step-by-step explanation:

3x+4y=-4

15x+20y=-22

——————————

-5(3x+4y)=-5(-4) multiply 1st equation by -5 so you can eliminate the variables

-15x-20y=20. Modified 1st equation

15x+20y=-22. 2nd equation

0+0=-2. Added two equations together

since 0 does not equal -2, there is no solution.

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