Determine if the following system of equations has no solutions ......................

Mathematics

1 answer:

topjm [15]3 years ago

8 0

Answer:

No solutions

Step-by-step explanation:

3x+4y=-4

15x+20y=-22

——————————

-5(3x+4y)=-5(-4) multiply 1st equation by -5 so you can eliminate the variables

-15x-20y=20. Modified 1st equation

15x+20y=-22. 2nd equation

0+0=-2. Added two equations together

since 0 does not equal -2, there is no solution.

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the multiplying by 3 is optional...I just did it because it is easier to work with equations when there are no fractions.

18j + n = 402....multiply by -3
j + 3n = 93
----------------
-54j - 3n = - 1206 (result of multiplying by -3)
j + 3n = 93
----------------add
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Read 2 more answers

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DaniilM [7]

Answer:

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