Let be an exponential function of the form $y = A\cdot e^{B\cdot x}$ , where $A$ and $B$ are real numbers. A horizontal asymptote exists when $e^{B\cdot x} \to 0$ , which occurs for $B\cdot x \to - \infty$ .

For this function, the horizontal asymptote is represented by $y = 0$ and to change the value of the asymptote we must add the parent function by another real number ( $C$ ), that is to say:

$y = A\cdot e^{B\cdot x} + C$ (1)

In this case, we must use $C = -3$ to obtain an horizontal asymptote of -3. Thus, the right choice is: A whole number constant could have been subtracted from the exponential expression.

To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280

3 0

2 years ago

Read 2 more answers

Pat is saving money to buy a bicycle. The amount he has saved is shown in the table below.

professor190 [17]

Answer:

I think A and C

Step-by-step explanation:

5 0

2 years ago

Solve this quadratic equation using the quadratic formula. x2 + 8x - 5 = 0

jasenka [17]

X^2 + 8x - 5 = 0
a = 1, b = 8, c = -5
x = ( - 8 + - sqrt(64 - 4*1*-5))/2
x = ( -8 + - sqrt(64+20))/2
x = ( -8 + - sqrt (84))/2
x = ( - 8 + - 2sqrt21))/2
x = -4 + - sqrt21

7 0

2 years ago