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ehidna [41]
2 years ago
13

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Mathematics
1 answer:
Ann [662]2 years ago
3 0
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

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Slope is y2-y1/x2-x1
(2,-5) can be your x1 and y1
(7,1) can be your x2 and y2
1-(-5)/7-2
1+5/5
6/5
The slope of the line is 6/5
Hope I helped!
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I roll a standard six-sided die 6 times in a row. What is the probability that the numbers
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6 0
3 years ago
If tan theta = startfraction 11 over 60 endfraction, what is the value of cot theta?
Dennis_Churaev [7]

The value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

Given that trigonometric ratio:

tan\theta = \frac{11}{60}

<h3>What is the tangent of an angle?</h3>

The tangent of an angle is the ratio of the opposite side(to that angle) to the adjacent side(to that angle).

So, for the given problem

Opposite side to \theta = 11

Adjacent side to \theta = 60

So, cot \theta =\frac{AdjacentSide }{OppositeSide}

cot\theta =\frac{60}{11}

Therefore, the value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

To get more about trigonometric ratios visit:

brainly.com/question/24349828

6 0
2 years ago
15
Makovka662 [10]

Answer:

Option A ( -3/2 , \frac{-3\sqrt{3} }{2} )

Step-by-step explanation:

  • According to Question, The Spinner Rotate 600* Thus after Completing 360* it Comes Exactly Where It Started . Now again rotate It 180* .
  • Now We Are on ( -X axis ) & Completed 360*+180*=540* Rotation
  • Now After Rotate It 60* More we come in Third Quadrant & Here In Third Quadrant Only Tangent & Cotangent Is Positive .(Sine & Cosine is Negative)  

(For Diagram, Please Find in attachment)

Now In Triangle OAB

  • Cos60* = OA / OB

        1/2 = -X / 3 Thus X= -3/2

  • Sin60* = AB / OB

        \sqrt{3}/2 = -Y / 3 Thus Y = -\sqrt{3} * 3 /2

6 0
2 years ago
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