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Sever21 [200]
3 years ago
7

Need help with this answer please

Mathematics
1 answer:
MrRa [10]3 years ago
5 0
The answer is b i hope this helps

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Find an equation for the line that passes through the points (1, -1) and (-3, 1).
saul85 [17]

Answer:

<h3>y = - 1/2x - 1/2</h3>

Step-by-step explanation:

Equation of line is y = mx + c

where m is the slope

c is the y intercept

Slope of the line using points

(1, -1) and (-3, 1) is

m =  \frac{1 + 1}{ - 3 - 1}  =  -  \frac{2}{4}  =  -  \frac{1}{2}

Equation of the line using point

( 1 , - 1) and slope - 1/2 is

y + 1 =  -  \frac{1}{2} (x - 1) \\ y + 1 =  -  \frac{1}{2} x +  \frac{1}{2}  \\ y =   - \frac{ 1}{2} x +  \frac{1}{2}  - 1 \\ y =  -  \frac{1}{2} x -  \frac{1}{2}

Hope this helps you.

3 0
3 years ago
You are at a European beach with 60 other visitors. 36 of them speak English. If you randomly meet two people on the beach, what
Kaylis [27]

Answer:

Assuming I'm one of the 36 English speakers and the other 24 speak Spanish for illustration purposes.  The problem can be modeled as 59 marbles with 35 E and 24 S marbles as N = 59 possible outcomes = n(E) + n(S) = 35 + 24.

So I reach into the pile of marbles (on the beach) and the probability that it's p(E) = n(E)/N = 35/59 = 0.593220339 when I meet the one person. ANS

I assume I remember that first person; so I remove him from the marbles (by avoiding him on the beach) and now my probability is p(E and E) = n(E)/N * n(E)-1/(N - 1) = 35/59*34/58 = 0.347749854 ANS

Following the same logic p(E and E and E) = 35/59*34/58*33/57 = 0.201328863 ANS

This last one is different from the first three.  This one is p(E >= 1|4 attempts).  We can trace out a probability tree to identify those branches that contain at least one E event.  So:

EEEE p() = 35/59 * 34/58 * 33/57 * 32/56 =  

EEES p() = 35/59 * 34/58 * 33/57 * 24/56 =

EESE p() = 35/59 * 34/58 * 24/57 * 33/56 =

ESEE p() = 35/59 * 24/58 * 34/57 * 33/56 =

SEEE p() = 24/59 * 35/58 * 34/57 * 33/56 =

EESS p() = 35/59 * 34/58 * 24/57 * 23/56 =

ESES p() = 35/59 * 24/58 * 34/57 * 23/56 =

SEES

SESE

SSEE

ESSS  And so on, but...a big BUT...why do all this when

SESS

SSES

SSSE

SSSS

p(E>=1|4) = 1 - p(S and S and S and S) = 1 - 24/59 * 23/58 * 22/57 * 21/56 = 0.976652619   ANS.  In other words we find the probability of not meeting an Englishman and take 1 minus that value to find the probability of meeting at least one.

00

Step-by-step explanation:

3 0
3 years ago
Select the best attribute for the angle pair formed by two parallel lines intersected
Inga [223]

Answer:

Corresponding Angles sum to 180°

Step-by-step explanation:

If a pair of parallel lines is cut by transversal that is not perpendicular to the parallel lines as shwon in the figures (attached below), then;

Four angles are acute, and four are obtuse.

  • All four acute angles are equal: 2=3=6=7
  • All four obtuse angles are equal: 1=4=5=8
  • The sum of acute and obtuse angles is 180:                                          for example, 1+2=180, 3+4=180, 5+6=180, 7+8=180

so the best attribute for the angle pair formed by two parallel lines intersected  by a transversal is that Corresponding Angles sum to 180°.

7 0
3 years ago
THE property of two rational numbers is -28/81. If one of them is -2/3, then find the other.
KiRa [710]
The answer is:
(-28/81)/(-2/3) = -84/(-162) = 42/81

Work
Think of this simple question:
Two number when multiplied together give 15. If one number is 5, then the other is (15/5)=3.
4 0
3 years ago
Peter weighs is 105 kg. His wants to lose 500 g per week. How many weeks will it take for him to have
ziro4ka [17]

Answer:

30 weeks

Step-by-step explanation:

105-90

=15 kg

15kg= 15000g

15000g/500g

=30 weeks

plz mark me as brainliest.

6 0
3 years ago
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