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3 years ago

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Inside the square ABCD, side 15 cm, the point M is considered, so that the triangle ABM is equilateral. Show that:

2 answers:

katovenus [111]3 years ago

8 0

Answer:

Step-by-step explanation:

a) area of square: 15 x 15 = 225 cm²

b) The steps are illustrated in the picture.

ΔADM ≅ ΔBCM (sas)

DM = CM

ΔMDC is isoceles

Vlad1618 [11]3 years ago

3 0

Answer:

a) 15*15=225 that is the area

b)see picture that I drew (sorry I have terrible drawing skills on a computer) but in a an isosceles triangle the two legs are congruent and the base is not when you cut a square diagonally as you have done this one the base will not be the same as the other two legs.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

we know that

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3 years ago

Write an equation in slope-intercept form for the line that has the given slope and contains the point. Please show some work.(

zavuch27 [327]

Answer:

An equation in the slope-intercept form will be:

$y=\frac{-1}{2}x+0$

Step-by-step explanation:

Given the points

(4,-2)

(2,-1)

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$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(4,\:-2\right),\:\left(x_2,\:y_2\right)=\left(2,\:-1\right)$

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We know that the slope-intercept form of the line equation is

$y=mx+b$

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substituting the values m=-1/2 and the point (4, -2) to determine the y-intercept i.e. 'b'.

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$-2=\frac{-1}{2}\left(4\right)+b$

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$b=0$

substituting the values m=-1/2 and b=0 to determine the line equation in slope-intercept form

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Thus, an equation in the slope-intercept form will be:

$y=\frac{-1}{2}x+0$

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3 years ago

How do i rearrange this equation into y=mx+b? y = - x - 5

MissTica

The Solution:

Given:

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Required:

To write the given equation in the form below:

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Clearly, the given equation is already in the required form.

The parameters are:

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3 years ago

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olga2289 [7]

Answer:

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3 years ago