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2 years ago

5

Three friends decide to share the cost to rent an apartment equally. The apartments that they are considering cost at least 1 20

0 per month. Write and solve an inequality to represent each person's share of the rental cost

1 answer:

deff fn [24]2 years ago

5 0

Each persons share of rental will cost at least 400$ per month!!

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Bus A leaves the station every 30 mins bus b leaves the station every 20 mins at 10 am both buses leave the station together wor

denis-greek [22]

Answer: 11am

Step-by-step explanation:

To solve this, we have to calculate the lowest common multiple of 20 and 30. This will be:

20 = 20, 40, 60, 80, 100

30 = 30, 60, 90, 120, 150.

Here, the lowest common multiple is 60.

Therefore, we add 60 minutes to 10am. This will be:

= 10am + 1 hour

= 11 am

The next time that both buses leave at the same time would be 11am

3 0

3 years ago

Rectangle Given:1=15 m, w=6m,A=

sashaice [31]

Answer:

$90m^2 and 144 m^2$

Step-by-step explanation:

Given :

Length of the rectangle (l)=15m

Width of the rectangle (w)= 6 m

Area of the rectangle can be calculated as :

$A=l*w\\A=(15)(6)\\A=90 m^2$

Now,

Side of square (s)=12 m

Area of the square can be find:

$A=s^2\\A=12^2\\A=144 m^2$

6 0

3 years ago

The slope of the line passing through the points (0, 3) and (5, 7) is

icang [17]

Slope formula: Change in y over change in x

Change in y: +4
Change in x: +5

Slope: 4/5

Hope this helps :)
Please give brainliest

7 0

3 years ago

A Ferrari is heading south at a constant speed on Broadway (a north/south street) at the same time a Mercedes is heading west on

Studentka2010 [4]

Answer:

49.92 miles/hour

Step-by-step explanation:

32 miles/hour = 32 * 5280 = 168960 ft/hour

For the collision to occur, both cars must arrive at the intersection at the same time.

The time it takes for the Mercedes to travel 400 feet at the rate of 168960 ft/hour is 400 / 168960 = 0.002367 hours

So the Ferrari should take the same time to travel 624 feet as well, its speed would be

624 / 0.002367 = 263577.6 ft/hour or 263577.6 / 5280 = 49.92 miles/hour

5 0

3 years ago

An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume

Lynna [10]

Answer:

a) $21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

b) $ME=2.58\frac{52}{\sqrt{350}}=7.17$

c) $ME=2.58\frac{52}{\sqrt{100}}=13.42$

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$\bar X=21$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=52$ represent the population standard deviation

n=350 represent the sample size

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

Part b

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{350}}=7.17$

Part c

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{100}}=13.42$

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0

3 years ago