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Elodia [21]
3 years ago
12

the mean of four consecutive even numbers is 15.the greatest of these numbers is a1.the least of these numbers is a2.

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0
Hello,

I suppose you want the 4 numbers.

Let's call the numbers 2n,2n+2,2n+4,2n+6
2n+2n+2+2n+4+2n+6[=8n+12=15*4\\
8n+12=60\\
8n=48\\
n=6\\\\
2n=12\\
2n+2=14\\
2n+4=16\\
2n+6=18\\



skelet666 [1.2K]3 years ago
3 0

Let x be the first even number. Then adding 2 consecutively gives us the subsequent even numbers. That is

x,x+2,x+4,x+6

From the question, the mean of these four numbers is 15. That is;

\frac{\sum x}{n} =15

\Rightarrow \frac{x+(x+2)+(x+4)+(x+6)}{4} =15

\Rightarrow \frac{x+x+2+x+4+x+6}{4} =15

\Rightarrow \frac{x+x+x+x+2+4+6}{4} =15

\Rightarrow \frac{4x+12}{4} =15

Multiply both sides by 4 to obtain,

\Rightarrow 4\times \frac{4x+12}{4} =4 \times15

\Rightarrow 4x+12 =60

\Rightarrow 4x =60-12

\Rightarrow 4x =48

Divide both sides by 4 to obtain,

x =12

<h2>Hence the greatest of the numbers is 12+6=18</h2><h2>and the least of the numbers is 12.</h2>


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